2CH₃COOH(aq) + Zn(s) → Zn(CH₃COO)₂(aq) + H₂(g)
2CH₃COOH(aq) + BaO(s) → Ba(CH₃COO)₂(aq) + H₂O(l)
CH₃COOH(aq) + NaOH(aq) → CH₃COONa(aq) + H₂O(l)
Answer: -64.1 kJ.
Explanation:
According to first law of thermodynamics:
=Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done by the system= {Work is done by the system is negative as the final volume is greater than initial volume}
w = -855 Joules = 0.855 kJ (1kJ=1000J)
q = -65.0 kJ {Heat released by the system is negative}
Thus the change internal energy (ΔE) for a system that is giving off 65.0 kJ of heat and is performing 855 J of work on the surroundings is -64.1 kJ.
im pretty sure it is B. A needle rubbed with a magnet is a temporary magnet
Answer:
1200 mL
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 400 mL.
Initial pressure (P1) = 600 mmHg.
Final volume (V2) =..?
Final pressure (P2) = 200 mmHg
Step 2:
Determination of the final volume i.e the new volume of the gas.
Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:
P1V1 = P2V2
600 x 400 = 200 x V2
Divide both side by 200
V2 = (600 x 400) /200
V2 = 1200 mL
Therefore, the new volume of the gas is 1200 mL.
Answer:
6moles of water
Explanation:
Given parameters:
Number of moles of oxygen = 3moles
Reaction equation:
2H₂ + O₂ → 2H₂O
Unknown:
Number of moles of water formed = ?
Solution:
To solve this problem;
compare the number of moles in the reaction.
1 mole of oxygen gas will produce 2 mole of water
3 moles of oxygen gas will produce 3 x 2 = 6moles of water.