<span>the rate decreases should be your answer</span>
Answer:
V₂ = 1.48 L
Explanation:
Given data:
Initial volume = 1.23 L
Initial pressure = 755 mmHg (755/760 =0.99 atm)
Initial temperature = 0 °C (0 +273 = 273 K)
Final temperature = 50°C (50+273 = 323 K)
Final volume = ?
Final pressure = 0.97 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.99 atm × 1.23 L × 323 K / 273 K × 0.97 atm
V₂ = 393.32 atm .L. K / 264.81 atm.K
V₂ = 1.48 L
Answer:
Under high temperatures and low pressure, gases behave the most ideal.
Explanation:
Low pressure reduces the effect of the finite size of real particles by increasing the volume around each particle, and a high temperature gives enough kinetic energy to the particles to better overcome the attractions that exist between real particles. (Prevents sticking.)
In summary, real gases behave more like ideal gases when they are far away from a phase boundary, (condensation or freezing).
Answer:
a) 2.29E4
Explanation: 1kg = 1000g. to get mass in grams multiply 22.9 kg by 1000g then divide by 1 kg to cancel the kg.
b) 2,29E5 g
c) 2.29 E10 μg
