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slega [8]
3 years ago
12

A student mixed several different 12 mm plastic beads together by mistake. Luckily the beads had different densities. One group

of beads had a density of 0.6 g/cm3; the other beads had a density of 1.2 g/ cm3. Describe a method the student can use to sort the beads.
Chemistry
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

The answer is "Each student will get a glass of water and drop the bead into it  but the beads float 0.6 g / cm3 and slip down to 1.2 g / cm3

".

Explanation:

One's masses would've been dissimilar, even though their width and concentrations were also equal. Whenever the type-A mass is m,  then the type-B mass is 2 m. One should measure then, therefore.  

Water has a 1g / cm^3 density. Although Type A is higher than air, Type B is much more compact. it means will float if they place  it in water type-A where type-B sinks.

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Aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge. Please select the best answer fr
Luden [163]
<h2>Answer:</h2>

True

<h2>Explanation:</h2>

we can describe aptitude as an innate ability of a person to do something. There are different aptitude test in which we test the skills and ability to do different work or his attitude toward success or failure.

So, we can say that aptitude is the capacity to learn a particular skill or acquire a particular body of knowledge.

4 0
3 years ago
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The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
2 years ago
The energy and state changes that occur when freezing rain falls and solidfies on a wire fence
Alex787 [66]

Freezing rain is the term given to the precipitation of the rain sustained at temperatures below freezing by the ambient air mass, which results in freezing on encountering with the surfaces. Freezing rain is formed completely of liquid droplets, unlike sleet, ice pellets, or hail.  

The freezing rain falls and solidifies on a wire fence as the rain is changing from a liquid to a solid state by withdrawing thermal energy, ultimately resulting in freezing.  


6 0
3 years ago
Read 2 more answers
Why isn't geothermal energy used more often?
lianna [129]

Geothermal energy is not used more often because it's hard to find geothermal energy sources that are close to the surface (Option A).

<h3>What is Geothermal energy?</h3>

Geothermal energy is a special type of sustainable renewable source of clean energy that emerges from thermal (temperature) differences on the Earth, e.g., within geysers and similar geological formations.

In conclusion, geothermal energy is not used more often because it's hard to find geothermal energy sources that are close to the surface (Option A).

Learn more about Geothermal energy here:

brainly.com/question/19666326

#SPJ1

5 0
1 year ago
How does the A Hreaction relate to the A He of molecules involved in a reaction?
igor_vitrenko [27]

Answer:

B. ΔHreaction = ΔH°f reactants- ΔH°f products

Explanation:

<em>Using Hess's law, it is possible to sum ΔH of several related reactions to find ΔH of a particular reaction</em>.

Having in mind Hess's law, ΔH°f is defined as the change in enthalpy during the formation of 1 mole of substance from its constituent elements (That is, pure elements, mono or diatomics, that have a ΔH° = 0).

For example, in ΔH°f of H₂O, the equation is:

H₂(g) + 1/2O₂(g) → H₂O(g)

The constituent elements with ΔH°f = 0 are H₂(g) and O₂(g).

Now, using Hess's law, you can sum the ΔH°f of substance in a reaction as, for example:

NaOH + HCl → H₂O + NaCl. ΔHr

The ΔH°f for each substance in the reaction is:

NaOH: Na + 1/2H₂ + 1/2O₂ → NaOH <em>(1)</em>

HCl: 1/2H₂ + 1/2Cl₂ → HCl <em>(2)</em>

H₂O: H₂ + 1/2O₂ → H₂O <em>(3)</em>

NaCl: Na + 1/2Cl₂ → NaCl <em>(4)</em>

The algebraic sum of (3) + (4) is -(ΔH°f reactants):

H₂ + 1/2O₂ + Na + 1/2Cl₂ → NaCl + H₂O ΔH°f reactants

This reaction - {(1)+(2)} ΔH°f products

NaOH + HCl → H₂O + NaCl.

ΔHr = ΔH°f reactants- ΔH°f products

In the example, we obtain this relationship that can be expanded for all reactions. Thus, right answer is:

<h3>B. ΔHreaction = ΔH°f reactants- ΔH°f products</h3>

8 0
3 years ago
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