Answer:
4 (D): twice the voltage, and the same current will flow through each.
Explanation:
When we have batteries in series in a circuit, the equivalent voltage will be the sum of their voltages, and the current flowing through then will be the same.
These batteries are identical, so they have the same voltage, therefore when they are put in series, the equivalent voltage will be twice the voltage of one battery.
So the correct option is 4 (D): twice the voltage, and the same current will flow through each.
Answer:
I believe it is luminosity and distance
Explanation:
So B
Answer:
In a series circuit, the same amount of current flows through all the components placed in it. On the other hand, in parallel circuits, the components are placed in parallel with each other due to which the circuit splits the current flow.
To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,
I = q*N
Here q is Flow of electric charge in one second and N the number of electron flow per second.
A the same time the power is described as the applied voltage for the current.
P = VI
We know the charge of electron, 
Coulombs, then the current is
And the power in the Beam is
Answer:
25%
Explanation:
use F=mg
then use the answer you get from that and plug it into W=Fxh
take that answer and divide it by 400 J and multiply by 100
round to sig figs
