80 joule is momentarily stored in each spring
<em><u>Solution:</u></em>
Given that,
The coil springs on a car's suspension have a value of k = 64000 N/m
When the car strikes a bump the springs briefly compress by 5.0 cm (.05 m)
By compressing the spring, we apply a force over a distance
As a result we have done work on the spring
Doing work means that we have transferred energy to spring in form of elastic potential
Therefore,
k = 64000 N/m
x = 0.05m
<em><u>The elastic potential energy is given as:</u></em>
![PE = \frac{1}{2}kx^2](https://tex.z-dn.net/?f=PE%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E2)
Where, "k" is the spring constant and "x" is the displacement
![PE = \frac{1}{2} \times 64000 \times 0.05^2\\\\PE = 32000 \times 0.0025\\\\PE = 80](https://tex.z-dn.net/?f=PE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2064000%20%5Ctimes%200.05%5E2%5C%5C%5C%5CPE%20%3D%2032000%20%5Ctimes%200.0025%5C%5C%5C%5CPE%20%3D%2080)
Thus 80 joule is momentarily stored in each spring