1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
4 years ago
11

How many atoms are in 0.8288 grams of sodium, Na?

Chemistry
2 answers:
harina [27]4 years ago
7 0
The answer can only be C

Blizzard [7]4 years ago
6 0
The answer is c.......................................
You might be interested in
Calculations of mass
Tems11 [23]

Answer:

I dont know i just wrote this because i have a question too sorry

6 0
3 years ago
What is the mass of the hydrogen peroxide that exactly fills a 200.0 mL container? The density of ethyl alcohol is 0.789 g/mL.
Tom [10]

Answer:

290 g of hydrogen peroxide would fill the 200.0 mL container

Explanation:

Given data:

Volume = 200.0 mL  

Mass of hydrogen peroxide = ?

Solution:

Density of hydrogen peroxide is 1.45 g/cm³.

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Now we can determine the mass of hydrogen peroxide.

D = m/v

1.45 g/cm³ = m/ 200.0 mL

1 mL = 1 cm³

m = 1.45 g/cm³× 200.0 cm³

m = 290 g

So 290 g of hydrogen peroxide would fill the 200.0 mL container.

5 0
4 years ago
What substance cannot be decomposed by physical or chemical means?
kakasveta [241]
Elements. Elements cannot be further separated as they are the most basic substances.
6 0
4 years ago
HELP PLEASE!!! FIRST PERSON TO ANSWER GETS 90 POINTS AND MARKED BRAINLIEST!
3241004551 [841]

Answer:

MgO has a highest melting point

C5Br has lowesst

Explanation:

It takes a lot of energy to overcome the strong electrostatic forces of attraction between oppositely charged ions, so ionic compounds have high melting and boiling points. ... Magnesium oxide is made from ions with two charges (Mg 2+ and O 2-) and so has a much higher melting point of 2852°C.

3 0
3 years ago
How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?
netineya [11]

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

12 × 250 = 4.5 × V₂

3000 = 4.5 × V₂

Divide both side by 4.5

V₂ = 3000 / 4.5

V₂ = 667 mL

Finally, we shall convert 667 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

667 mL = 667 mL × 1 L / 1000 mL

667 mL = 0.667 L

Thus, the volume of the solution prepared is 0.667 L

3 0
3 years ago
Other questions:
  • What evidence caused Thomson to change Dalton's solid sphere model into the plum pudding model?
    12·1 answer
  • How many ne atoms are contained in 32.0g of the element?
    8·1 answer
  • What's global warming <br>​
    9·2 answers
  • When HCl(g) reacts with O2(g) to form H2O(g) and Cl2(g), 6.84 kcal of energy are evolved for each mole of HCl(g) that reacts. Wr
    5·1 answer
  • If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
    9·1 answer
  • do ionic, covalent and metallic bonds form molecular or ionic compounds? HELP PLEASE I WILL MARK BRAINLIEST
    12·1 answer
  • HURRY PLS HELP
    8·1 answer
  • Given R=0.0821L⋅atm/mol⋅K, how many moles of gas are in a 1.25 L container at 300K and 2.07 atm?(1 point)
    11·2 answers
  • ( BRAINLIEST) Few drops of thymolphthalein indicator will change acid to...
    6·2 answers
  • When you are drying your hands underneath a hand dryer, this is an example ofA. RadiationB. ConductionC. ConvectionD. Convection
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!