If Car A has a greater momentum than Car B, what will happen to both vehicles immediately after they collide?

A Texas rancher wants to fence off his four-sided plot of flat land. He measures the first three sides, shown as A, B, and C in

xz_007 [3.2K]

The answer:
the full question is as follow:
A Texas rancher wants to fence off his four-sided plot of flat land. He measures the first three sides, shown as A, B, and C in Figure below , where A = 4.90 km and θC = 15°. He then correctly calculates the length and orientation of the fourth side D. What is the magnitude and direction of vector D?

As shown in the figure,
A + B + C + D = 0, so to find the magnitude and direction of vector D, we should follow the following method:
D = 0 - (A + B + C) ,
let W = - (A + B + C), so the magnitude and direction of vector D is the same of the vector W characteristics

Magnitude
A + B + C = (4.90cos7.5 - 2.48sin16 - 3.02cos15)I
+ (-4.9sin7.5 + 2.48cos16 + 3.02sin15)J
= 1.25I +2.53J
the magnitude of W= abs value of (A + B + C) = sqrt (1.25² + 2.53²)
= 2.82

the direction of D can be found by using Dx and Dy value
we know that tanθo = Dx / Dy = 1.25 / 2.53 =0.49
tanθo =0.49 it implies θo = arctan 0.49 = 26.02°

direction is 26.02°

4 0

3 years ago

In most circumstances, the normal force acting on an objectand

Lynna [10]

Answer:

Normal Force is usually perpendicular to the movement and static friction usually means that there is no movement.

Explanation:

The work donde by any force on an object is equal to the displacement of the object multiplied by the component of the force that is in the direction of the displacement.

Normal force is usually perpendicular to the movement, so there is no component in the direction of the displacement. This is why it is zero in most circumstances.

Static friction on the other hand, usually means that there is no movement at all (it's static). It means that there is no displacement between the object and ground (in most cases). If there is no displacement, there is no work.

4 0

3 years ago

Light enters air from water. The angle of refraction will be A. less than the angle of incidence. B. greater than or equal to th

Rina8888 [55]

Answer:

E. greater than the angle of incidence.

Explanation:

Snell's law states that:

$n_i sin \theta_i = n_r sin \theta_r$ (1)

where

$n_i, n_r$ are the refractive index of the first and second medium

$\theta_i, \theta_r$ are the angle of incidence and refraction, respectively

For light moving from water to air, we have:

$n_i = 1.33$ (index of refraction of water)

$n_r = 1.00$ (index of refraction of air)

Substituting into (1) and re-arranging the equation, we get

$\sin \theta_r = \frac{n_i}{n_r} sin \theta_i = 1.33 sin \theta_i$

which means that

$\theta_r > \theta_i$

so, the correct answer is

E. greater than the angle of incidence.

4 0

3 years ago

Read 2 more answers

Which of the following would most likely happen if water did not form hydrogen bonds?

Trava [24]

Option C is the correct answer

6 0

3 years ago

A proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.

lawyer [7]

The change in potential energy of the proton is 5.6 x $10^{-17}$ Joule

<h3>What is a Uniform Electric Field ?</h3>

A uniform electric field is where the electric field strength is the same at all points in the field. In the uniform field, the force experienced by a charge is the same no matter where it is placed in the field.

Given that a proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.

The distance d = 10 cm = 0.1 m

Electric field E = 3.5 KN/C

Proton charge q = 1.6 x $10^{-19}$ C

The Work done = Fd

but F = Eq

Recall that Electric field E = F/q = V/d

Where V = potential difference.

Let us first calculate the V

E = V/d

V = Ed

Substitute all the parameters into the formula above

V = 3.5 × 10³ × 0.1

V = 350 v

from F/q = V/d

make F the subject of formula and substitute it in work formula

F = Vq/d

W.D = Vq/d x d

W.D = Vq

Substitute all the parameters into the formula above

W.D = 350 x 1.6 x $10^{-19}$

W.D = 5.6 x $10^{-17}$ J

Work done = Energy = Potential Energy

Therefore, the change in potential energy of the proton is 5.6 x $10^{-17}$ Joule

Learn more about Electric Field here: brainly.com/question/14372859

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7 0

2 years ago