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3 years ago

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The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average speed of 216 km/h. (a) If the train goes

around a curve at that speed and the acceleration experienced by the passengers is to be limited to 0.060g, what is the smallest radius of curvature for the track that can be tolerated? (b) At what speed must the train go around a curve with a 1.80 km radius to be at the acceleration limit?

1 answer:

faust18 [17]3 years ago

6 0

Answer:

a) r = 6122 m and b) v = 32.5 m / s

Explanation:

a) The train in the curve is subject to centripetal acceleration

a = v2 / r

Where v is The speed and r the radius of the curve

They indicate that the maximum acceleration of the person is 0.060g,

a = 0.060 g

a = 0.060 9.8

a = 0.588 m /s²

Let's calculate the radius

v = 216 km / h (1000m / 1km) (1 h / 3600 s =

v = 60 m / s

r = v² / a

r = 60² /0.588

r = 6122 m

b) Let's calculate the speed, for a radius curve 1.80 km = 1800 m

v = √a r

v = √( 0.588 1800)

v = 32.5 m / s

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