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Ber [7]
4 years ago
13

The gravitational acceleration on the Earth's surface is ce of a plan et with the same size, but twice the mass? it be on the A.

16 fect B. 32 fect/second/second C. 64 f D. 128 foet/second second E. 8 feet 18-
Physics
1 answer:
KengaRu [80]4 years ago
8 0

Explanation:

The acceleration due to gravity is on Earth is given by :

g_e=\dfrac{GM_e}{R^2}..............(1)

Where

M is the mass of Earth

R is the radius of Earth

G is the universal gravitational constant

g_e=32\ ft/s^2

The formula for acceleration due to gravity on planet is given by :

g_p=\dfrac{GM_p}{R_p^2}..............(2)

Since, M_p=2M_e

From equation (1) and (2) :

\dfrac{g_p}{g_e}=\dfrac{M_p}{M_e}

g_p=2\times g_e

g_p=2\times 32\ ft/s^2

g_p=64\ ft/s^2

So, the acceleration on the planet is 64 feet per second square. Hence, this is the required solution.

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