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castortr0y [4]
3 years ago
8

32P has a half life of 14.0 days. If you order 60.0 grams of 32P and it took 46.7hrs from the time it was made to the time it wa

s delivered, how much radioactive 32P (in grams) did you actually receive?
Chemistry
1 answer:
8090 [49]3 years ago
7 0

Answer:

[A_t]=54.5\ g

Explanation:

Given that:

Half life = 14.0 days

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{14.0}\ days^{-1}

The rate constant, k = 0.04951 days⁻¹

Initial concentration [A₀] = 60.0 g

Time = 46.7 hrs

Considering, 1 hr = 0.041667 days

So, time = 1.9458 days

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

So,  

[A_t]=60.0\times e^{-0.04951\times 1.9458}\ g

[A_t]=54.5\ g

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3 years ago
A mixture of hydrogen and argon gases is maintained in a 6.47 L flask at a pressure of 3.43 atm and a temperature of 85 °C. If t
11Alexandr11 [23.1K]

Answer:

The mixture contains 8.23 g of Ar

Explanation:

Let's solve this with the Ideal Gases Law

Total pressure of a mixture = (Total moles . R . T) / V

We convert T° from °C to K → 85°C + 273 = 358K

3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L

(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles

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3 years ago
Read 2 more answers
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