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castortr0y [4]
3 years ago
8

32P has a half life of 14.0 days. If you order 60.0 grams of 32P and it took 46.7hrs from the time it was made to the time it wa

s delivered, how much radioactive 32P (in grams) did you actually receive?
Chemistry
1 answer:
8090 [49]3 years ago
7 0

Answer:

[A_t]=54.5\ g

Explanation:

Given that:

Half life = 14.0 days

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{14.0}\ days^{-1}

The rate constant, k = 0.04951 days⁻¹

Initial concentration [A₀] = 60.0 g

Time = 46.7 hrs

Considering, 1 hr = 0.041667 days

So, time = 1.9458 days

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

So,  

[A_t]=60.0\times e^{-0.04951\times 1.9458}\ g

[A_t]=54.5\ g

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Vadim26 [7]

Answer:

Explanation:

The Hawaiian Islands were literally created from lots of volcanoes—they're a trail of volcanic eruptions. In the case of the Hawaiian Islands, the Pacific Plate is continually moving to the northwest over the Hawaiian hot spot. This movement caused the Hawaiian chain of islands to form.

8 0
3 years ago
Which of the following scientists was the first to determine the
Maru [420]

Answer:

Robert Boyle

Explanation:

Robert Boyle was an Irish chemist and is famously referred to as the first modern chemist. He was born on the 25th of January, 1627 in Lismore, Ireland and died on the 31st, December 1691, London, United Kingdom.

Robert Boyle was the first to determine the relationship between the pressure and volume of a gas.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Where;

V1 and V2 represents the initial and final volumes respectively.

T1 and T2 represents the initial and final temperatures respectively.

8 0
3 years ago
If a mixture of gases contained 78% nitrogen at a pressure of 984 torr and 22% carbon dioxide at 345 torr, what is the total pre
AysviL [449]

Answer:

P(total) = 1329 torr

Explanation:

Given data:

Pressure of nitrogen = 984 torr

Pressure of carbon dioxide = 345 torr

Total pressure of system = ?

Solution:

The given problem will be solve through the Dalton law of partial pressure of gases.

According to the this law,

The total pressure exerted by the mixture of gases is equal to the sum of partial pressure of individual gas.

Mathematical expression,

P(total) = P₁ + P₂ +.......+ Pₙ

Here we will put the values in formula,

P₁ = partial pressure of nitrogen

P₂ = partial pressure of carbon dioxide

P(total) = 984 torr + 345 torr

P(total) = 1329 torr

8 0
3 years ago
Suppose you put 50 ml of water in the can instead of 100 ml and heated it to 40 degrees instead of 20 degrees. in what ways if a
Alex
<span>Answer: Once these values are put into the equation delta Q=mc delta T it will give you the same value for Q (change in energy) if the same fuel is used 50mL will mean it gets heated quicker making the experiment quicker 200mL would take longer to heat for the same change in temperature causing a longer experiment.</span>
8 0
4 years ago
How many grams of ethylene glycol (c2h6o2) must be added to 1.00 kg of water to produce a solution that freezes at -5.00oc? (kf
leonid [27]

Answer: 167 g


Explanation:


1) The depression of the freezing point of a solution is a colligative property ruled by this equation:


ΔTf = i × m × Kf


Where:


ΔTf is the decrease of the freezing point of the solvent due to the presence of the solute.


i is the Van't Hoof factor and is equal to the number of ions per each mole of solute. It is only valid for ionic compounds. Here the solute is not ionice, so you take i = 1


Kf is the molal freezing constant and is different for each solvent. For water it is 1.86 m/°C


2) Calculate the molality (m) of the solution


ΔTf = i × m × Kf ⇒ m = ΔTf / ( i × Kf) = 5.00°C / 1.86°C/m = 2.69 m


3) Calculate the number of moles from the molality definition


m = moles of solute / kg of solvent ⇒ moles of solute = m × kg of solvent


moles of solute = 2.69 m × 1.00 kg = 2.69 moles


4) Convert moles to grams using the molar mass


molar mass of C₂H₆O₂ = 62.07 g/mol


mass in grams = number of moles × molar mass = 2.69 moles × 62.07 g/mol = 166.97 g ≈ 167 g

6 0
3 years ago
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