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nlexa [21]
3 years ago
12

Which general trends in first ionization energy and electronegativity values are demonstrated by group 15 elements as they are c

onsidered in order from top to bottom(1) The first ionization energy decreases and the electronegativity decreases.
(2) The first ionization energy increases and the electronegativity increases.
(3) The first ionization energy decreases and the electronegativity increases.
(4) The first ionization energy increases and the electronegativity decreases.
Chemistry
1 answer:
MaRussiya [10]3 years ago
3 0

Answer: (1) The first ionization energy decreases and the electronegativity decreases

Explanation:

When we move from top to bottom in a periodic table the atomic size of elements increases and it becomes easy to remove valence electron from the elements at low energy.Thus decrease in ionisation energy from top to bottom.

Metallic character increases as we move down into a group of a periodic table and metals have low electronegativity than non-metals. So, value of electronegativity decreases from top to bottom.

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77julia77 [94]

Answer:

7.38g HCl

Explanation:

Using H-H equation for acetic buffer:

pH = pKa + log [NaC2H3O2] / [HC2H3O2]

<em>Where pKa is -log Ka = 4.74 and [] could be taken as moles of each compound.</em>

The initial moles of each specie is:

[NaC2H3O2]:

0.500L * (0.665mol/L) = 0.3325moles

[HC2H3O2]:

0.500L * (0.475mol/L) = 0.2375 moles

That means total moles are:

[NaC2H3O2] + [HC2H3O2] = 0.57 moles <em>(1)</em>

And solving H-H equation for a pH of 4.21:

4.21 = 4.74 + log [NaC2H3O2] / [HC2H3O2]

0.29512 = [NaC2H3O2] / [HC2H3O2] <em>(2)</em>

Replacing (1) in (2):

0.29512 = 0.57mol - [HC2H3O2] / [HC2H3O2]

0.29512 [HC2H3O2] = 0.57mol - [HC2H3O2]

1.29512 [HC2H3O2] = 0.57mol

[HC2H3O2] = 0.44 moles

The HCl reacts with NaC2H3O2 producing HC2H3O2, that means you need to add:

0.44 moles - 0.2375 moles =

0.2025 moles of HCl

Using molar mass of HCl (36.45g/mol), to convert these moles to grams:

0.2025 moles * (36.45g/mol) =

<h3>7.38g HCl</h3>

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<u>Therefore, the cell obtains more calcium by the process of Primary active transport.</u>

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Explanation:

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