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3 years ago

According to the Doppler effect what appears to happen when a light source moves further away from an observer

Physics

2 answers:

schepotkina [342]3 years ago

8 0

Answer: Hello there!

When the source of light moves further away from the observer (or the observer moves further away from the light source), there is something called "redshift"

The observer sees the wavelength wider, which means that the frequency decreases. This phenomenon causes a shift in the color of the wave, which now looks more red.

ludmilkaskok [199]3 years ago

6 0

Answer: The correct answer is B. "the electromagnetic waves appear more red in color".

Explanation:

Scientists use the Doppler effect to understand the universe by determining the motion of the object.

Red shift: The apparent frequency of light decreases as the source object in space moves away from us. The light is shifted to red end. The apparent frequency decreases and there is increase in the wavelength of the light.

Blue shift: The apparent frequency of light increases as the object in space moves towards us. The light is shifted to blue end. In this case, there is decrease in the wavelength of the light. The frequency of the wave increases.

In the given problem, when the light source moves further away from an observer, the electromagnetic waves appear red in color.

Therefore, the correct option is (B).

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An archer draws her bow and stores 34.8 J of elastic potential energy in the bow. She releases the 63 g arrow, giving it an init

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Answer:

Approximately $71\%$ .

Explanation:

The formula for the kinetic energy $\rm KE$ of an object is:

$\displaystyle \mathrm{KE} = \frac{1}{2}\, m \cdot v^2$ ,

where

$m$ is the mass of that object, and
$v$ is the speed of that object.

Important: Joule ( $\rm J$ ) is the standard unit for energy. The formula for $\rm KE$ requires two inputs: mass and speed. The standard unit of mass is $\rm kg$ while the standard unit for speed is $\rm m \cdot s^{-1}$ . If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,

Convert the unit of the arrow's mass to standard unit:

$m = 63\; \rm g = 0.063\; \rm kg$ .

Initial $\rm KE$ of this arrow:

$\begin{aligned}\mathrm{KE} &= \frac{1}{2} \, m \cdot v^2 \\ &= \frac{1}{2}\times 0.063\; \rm kg \times \left(\rm 28 \; m \cdot s^{-1}\right)^2 \\ &\approx 24.696\; \rm J\end{aligned}$ .

That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:

$\displaystyle \frac{24.696\; \rm J}{34.8\; \rm J} \times 100\% \approx 71\%$ .

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3 years ago

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