Answer: a = 200 Ω, b = 7.5 mA
Explanation:
Re = 100 + 100 = 200 Ω
I = E/R = 1.5/200 = 0.0075 A
Answer:
Their measured results are closer to the exact or true value. Hence, their measured value is considered to be more accurate.
Explanation:
Considering the situation described above, the accuracy of a measured value depicts how closely a measured value is to the accurate value.
Hence, since the students' measured values have very low percent differences, it shows the similarity of computations or estimates to the actual values, which in turn offers a smaller measurement error.
Therefore, their measured results are closer to the exact or true value, which implies that their measured value is considered to be more accurate.
Answer:
The speed of the stone is
v = 7.45 m/s
Explanation:
Length, L=0.551m
maximum tension in the spring = 9.6%
So let speed of stone be
Tv = TH + 9.6/ 100 * TH
Tv - m*g = m*v^2/L
TH = m*v^2 / L
Factor mass to cancel in the equation
Solve to v
v^2= L*g*100 / 9.6
Replacing numeric:
v^2=0.551m*9.8m/s^2*100 / 9.6
v = sqrt( 56.24 m^2/s^2)
v = 7.45 m/s
Answer:
Frequency of sound wave = 198.83 hertz (Approx.)
Explanation:
Given:
Velocity of sound wave in air = 340 m/s
Wavelength = 1.71 meter
Find:
Frequency of sound wave
Computation:
Frequency = Velocity / Wavelength
Frequency of sound wave = Velocity of sound wave in air / Wavelength
Frequency of sound wave = 340 / 1.71
Frequency of sound wave = 198.8304
Frequency of sound wave = 198.83 hertz (Approx.)