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4 years ago

15

Look at the advertisement. A poster that reads, "There's more to resistors than resistance. If you're really serious about cost,

be serious about quality." with tools. Which persuasive media technique is used in this advertisement

2 answers:

ozzi4 years ago

7 0

Options:

universal appeal

flattery

association

bandwagon

Answer: Association

Explanation: Advertisement is a marketing technique through which business organisations utilize the opportunities provided by both the print, electronic and other channels of communication to market a product to the target audience.

Association Advertising is a type of Advertising where certain attributes which have been known to be associated with good and quality products are used to market the products to the target audience.

nadezda [96]4 years ago

7 0

Explanation:

It's Flattery guys

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Calculate the angular velocity and linear velocity of both wheels assuming the larger wheel rotates at 120 revolutions per mi

IRINA_888 [86]

<span>120 revolutions per min is (20RPM)
120revolutions is 240 Pi radians (because 1 revolution is 2Pi rad)

angular velocity
w= 240Pixf, f is the frequency and f= 1/T, T =1mn=60s=period, so f=1/60=0.01Hz
so w = 240*Pi*0.01=12.56 rad /s
linear velocity can be found with
V =Rx w,
V=12.56 R the value depends on what value is the radius of both wheels

</span>

6 0

3 years ago

An 89.0 kg fullback moving east with a speed of 5.6 m/s is tackled by an 85.0 kg opponent running west at 2.84 m/s, and the coll

Korolek [52]

Answer:

a. $v_f=1.477m/s$

b. Δ $K=1558.3J$

c. $E_k=1034.7 J$

Explanation:

a).

Momentum conserved

$p_{ix}=p_{fx}$

$m_1*v_1+m_2*v_2=(m_1+m_2)*v_f$

$v_f=\frac{m_1*v_1+m_2*v_2}{m_1+m_2}$

$v_f=\frac{89.0kg*5.6m/s+85.0kg*-2.84m/s}{(89.0+85.0)kg}$

$v_f=1.477m/s$

b).

Δ $K=K_i-K_f$

$\frac{1}{2}*m_1*v_1^2+\frac{1}{2}*m_2*v_2^2=\frac{1}{2}*(m_1+m_2)*v_f^2$

$\frac{1}{2}*89.0kg*(5.6m/s)^2+\frac{1}{2}*85.0kg*(2.84m/s)^2=\frac{1}{2}*(89.0+85.0)kg*(1.447m/s)^2$

Δ $K=1558.3J$

c).

$E_k=\frac{1}{2}*89kg*(5.8m/s)^2-\frac{1}{2}*(85+89)kg*(1.44m/s)^2$

$E_k=1034.7 J$

d).

All of which has been lost as mechanical energy, and is now thermal energy warmer football players, noise a loud crunch for example.

8 0

3 years ago

A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k

Luba_88 [7]

Answer:

The frictional force $F_{fri} =$ 6.446 N

The acceleration of the block a = 6.04 $\frac{m}{s^{2} }$

Explanation:

Mass of the block = 3.9 kg

$\theta = 40$ °

$\mu$ = 0.22

(a). The frictional force is given by

$F_{fri} = \mu R_{N}$

$R_{N} = mg \cos \theta$

$R_{N} =$ 3.9 × 9.81 × $\cos 40$

$R_{N} =$ 29.3 N

Therefore the frictional force

$F_{fri} =$ 0.22 × 29.3

$F_{fri} =$ 6.446 N

(b). Block acceleration is given by

$F_{net} = F - F_{fri}$

F = 30 N

$F_{fri}$ = 6.446 N

$F_{net}$ = 30 - 6.446

$F_{net}$ = 23.554 N

The net force acting on the block is given by

$F_{net} = ma$

23.554 = 3.9 × a

a = 6.04 $\frac{m}{s^{2} }$

This is the acceleration of the block.

8 0

3 years ago

Why is hygiene a valued health practice in workout facilities?

MariettaO [177]

This is one method of how infectious diseases like skin infections spread. Keeping the gym clean is essential to maintaining everyone's health and safety.

<h3>Which skin illness is the worst?</h3>

Necrotising fasciitis is just a severe infection of the skin, including tissue beneath the skin, and the fascia (the fibrous tissue that divides muscles and organs), which causes necrosis, or the death of tissue. If not identified and treated promptly, the infection spreads quickly, is lethal.

<h3>A skin infection: how do you treat it?</h3>

Depending on the infection's origin and intensity, different treatments are available. It may take days or weeks for some viral skin infections to heal on their own. Antibiotics taken orally or administered topically to the skin are frequently used to treat bacterial infections.

To know more about skin infection visit;

brainly.com/question/7656575

#SPJ1

4 0

1 year ago

A 0.017 g coin sliding to the right at 0.255 m/s makes an elastic head-on collision with a 0.040 g coin that is initially at res

zysi [14]

Answer:

$\approx 0.154\:\mathrm{m/s}$

Explanation:

In all collisions, whether elastic or inelastic, momentum must be conserved. Therefore, we can write an equation using the conservation of momentum:

$m_{c1}v_{c1,i}+m_{c2}v_{c2,i}=m_{c1}v_{c1,f}+m_{c2}v_{c2,f}$

Solving for $v_{2c,f}$ :

$0.000017\cdot 0.255+0.000040\cdot0=0.000017\cdot (-0.108)+0.000040\cdot v_{c2,f},\\v_{c2,f}\approx \boxed{0.154\:\mathrm{m/s}}$

*Notes:

-It's important to convert g to kg, as kg is the SI unit of mass

-The negative sign in a velocity measure represents direction

-Since the velocity we solved for is positive, it implies that the direction is to the right

5 0

3 years ago