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Leto [7]
3 years ago
13

A gas occupies a volume of 8.60 L at 45C and 764 torr. What pressure would it occupy if the volume is adjusted to 13.3 L at 20C?

Chemistry
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

455 Torr

Explanation:

To get the correct answer, we employ the use of the General gas equation.

In its general form, the General gas equation can be written as:

P1V1/T1 = P2V2/T2

Defining the parameters;

P1 = 764 torr

V1 = 8.6L

T1 = 45 degrees Celsius = 273.15+ 45 = 318.15K

P2 = ?

V2 = 13.3L

T2 = 20 degrees Celsius = 273.15 + 20 = 293.15K

Rearranging the equation yields: P2 = P1V1T2/T1V2

Substituting the values:

P2 = (764 * 8.6 * 293.15)/(318.15 * 13.3)

P2= 455.2 Torr

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The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the
weqwewe [10]

Answer:

The pressure increases by a factor of four.

Explanation:

Let's consider a gas at a given temperature and pressure (T₁, P₁). The absolute temperature of a gas is increased four times (T₂ = 4 T₁) while maintaining a constant volume. We can assess the effect on the pressure (P₂) by using Gay Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = P₁ × 4 T₁/T₁

P₂ = 4 P₁

The pressure increases by a factor of four.

4 0
3 years ago
The density of an unknown gas is 4. 20 grams per liter at 3. 00 atmospheres pressure and 127 °c. what is the molecular weight of
Kryger [21]

The molecular weight of this gas will be 45 g/mol .

The state equilibrium equation for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has significant drawbacks, it represents a decent approximation of the activity of many gases under various conditions.

Ideal gas law can be expressed as:

PV =nRT

Calculation of molecular weight by using ideal as law.

Given data:

P = 3 atm

T = 127 °c

Density =  4. 20 grams per liter

PV =nRT

where p is pressure , T is temperature and R is gas constant.

PV = gram / molecular weight RT

Molecular weight = (g/v)( 1/P) RT

Putting the given data in above equation.

Molecular weight =4.20 × 1/ 3× 400 × 0.0831

Molecular weight = 45 g/mol.

To know more about Molecular weight

brainly.com/question/27988184

#SPJ4

4 0
2 years ago
Name one object that would be considered a gas. Describe how the atoms move in a gas.
soldi70 [24.7K]

Answer:

gas vibrate and move freely at high speeds. liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place.

Explanation:

6 0
3 years ago
Read 2 more answers
How many moles of BCl3 are needed to produce 10.0 g of HCl(aq) in the following reaction? (HCl molar mass is 36.46 g/mol).
Scilla [17]

Answer:

Moles of BCl₃ needed = 0.089 mol

Explanation:

Given data:

Moles of BCl₃ needed = ?

Mass of HCl produced = 10.0 g

Solution:

Chemical equation:

BCl₃ + 3H₂O  →     3HCl + B(OH)₃

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 36.46 g/mol

Number of moles = 0.27 mol

Now we will compare the moles of HCl with BCl₃.

               HCl             :           BCl₃

                 3               :             1

             0.27             :            1/3×0.27 = 0.089 mol

6 0
3 years ago
Which statement about the ocean is true?
nika2105 [10]
The answer is c mate
3 0
3 years ago
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