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soldi70 [24.7K]
3 years ago
13

A car accelerates from rest to a speed 20 m/s in 12 s. Find the distance the car travels this time

Physics
1 answer:
Andrew [12]3 years ago
6 0
The first thing we need to do is figure out what equation to use. We will use the following kinematic equation...

Δx = (final velocity + initial velocity) x time / 2

We know that the car accelerates from rest, so initial velocity = 0 m/s
We also know final velocity = 20 m/s and time = 12s

Now we just need to plug everything in.

Δx = (20 x 12)/2 = 120 meters
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Answer:

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An arrow is shot vertically upward at a rate of 250ft/s. Use the projectile formula h=−16t2+v0t to determine at what time(s), in
SIZIF [17.4K]

Answer:

The arrow is at a height of 500 feet at time t = 2.35 seconds.

Explanation:

It is given that,

An arrow is shot vertically upward at a rate of 250 ft/s, v₀ = 250 ft/s

The projectile formula is given by :

h=-16t^2+v_ot

We need to find the time(s), in seconds, the arrow is at a height of 500 ft. So,

-16t^2+250t=500

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So, the arrow is at a height of 500 feet at time t = 2.35 seconds. Hence, this is the required solution.

6 0
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Oxana [17]

Answer:

energy is stored is 2.2 × 10⁻¹³ J

Explanation:

The capacitance  of the cell is given with the expression

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Now given that; the diameter is 50,

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C = [9 ( 8.85 × 10⁻¹² C²/N.m²  × 7850×10⁻¹² m² )] / 7×10⁻⁹ m

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E = 1/2 × CV²

E = 1/2 × (8.93 × 10⁻¹¹ F) × ( 70 × 10⁻³ V)²

E = 2.2 × 10⁻¹³ J

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Answer:

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Explanation:

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