Answer:
(a) the height in the open water column is: 18.15 (ft), (b) the gauge pressure acting on the bottom tank surface AB is: 8.73 (Psi) and (c) the absolute pressure of the air in the top of the tank with local atmospheric pressure at 14.7 Psi will be: 21.7 (Psi).
Explanation:
We need to apply the Pascal's Law, () where P is pressure, γ is the specific weight of the fluid and h is the height of the column of fluid, to find the pressure at differents points in the tank (see attached). First we need to assume a property of the water called specific weight as: 62.4 (lbf/ft^3) or 0.03612 (lbf/in^3). Then knowing that 1 feet as the same as 12 inches and appling Pascal's Law, we get: and the other hand, we have: and knowing that the pressure at point C and point D are the same, we can find the h as:, so getting h=217.75(in) or 18.15(ft) (a). Now similarly to find the gauge pressure acting on the bottom of the tank surface AB we can apply Pascal's Law as: (b). Finally we can find the absolute pressure of the air in the top of the tank, assuming a local atmospheric pressure as 14.7 (Psi) so: (c).
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Ultrasound is a frequency where higher than that which is audible. So the answer is "high frequency".
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Answer is Weaker. If it is talking about the objects' gravitational forces.
Answer: The cake would be 100F after about 47 minutes
Explanation:
Initial temperature = 210F
Time at 140F = 30 minutes
At 140F the cake has lost (210-140)F
= 70F
70F is lost on 30minutes
Rate of temperature reduction
= (70/30) F/min
= 7/3F/min
To lose 110F from 210 to 100F
Temp/time = 7/3
110/t = 7/3
Cross multiply
t = 330/7
t = 47.1429minutes ~ 47min
D. sample 4 would be your answer