All categories

3 years ago

What hazard is associated with ionizing radiation?

2 answers:

8 0

Acute health effects such as skin burns or acute radiation syndrome can occur when doses of radiation exceed certain levels.

kogti [31]3 years ago

8 0

Answer:

Skin burns and increasing effect of cancer.

Explanation:

Ionizing radiations are majorly produced during radioactivity process. Radioactivity is the disintegration of radioactive elements to produce energy. This energy produced are in form of ionizing radiations. Most elements that undergoes radioactivity are unstable and they produce some electromagnetic radiations like gamma rays, alpha rays and beta rays. Some of this radiations are harmful to the health and serves as threats and hazards to humans. Some of this hazards caused by this radiations includes skin burns and cancer which are due to our exposure to sources of ionizing radiations some of which are x-rays in hospitals, soil and vegetation.

You might be interested in

What are two ways in which all types of precipitation are alike

Digiron [165]

1. they all come from the clouds 2.they are all formed by precipatation. hope this helps enjoyyyyyy!!!!!!!!!!!!!

7 0

3 years ago

The magnetic field is 0.0 2M from the wire is 0.1 T what is the magnitude of the magnetic field 0.0 1M from the same wire

Kisachek [45]

Answer:

0.2 T

Explanation:

Magnetic field is inversely proportional to the distance from wire since the distance is halved therefore magnetic field will be doubled.

4 0

3 years ago

How do reflection and refraction of waves affect communication?

romanna [79]

Answer:

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

5 0

3 years ago

Read 2 more answers

Where do you feel that you are traveling at the fastest speed when on the swing?

il63 [147K]

Answer:

Explanation:

I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.

7 0

3 years ago

Read 2 more answers

Two parallel conducting plates are separated by 9.2 cm, and one of them is taken to be at a potential of zero volts.What is the

True [87]

Answer:

$E=54V/cm$

$\Delta V=496.8V$ between the plates.

Explanation:

The equation for change of voltage between two points separated a distance d inside parallel conducting plates (<em>which have between them constant electric field</em>) is:

$\Delta V=Ed$

So to calculate our electric field strength we use the fact that the potential 8.8 cm from the zero volt plate is 475 V:

$E=\frac{\Delta V}{d}=\frac{475 V}{8.8cm}=54V/cm$

And we use the fact that the plates are 9.2cm apart to calculate the voltage between them:

$\Delta V=Ed=(54V/cm)(9.2cm)=496.8V$

8 0

3 years ago