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melisa1 [442]
3 years ago
12

What hazard is associated with ionizing radiation?

Physics
2 answers:
Talja [164]3 years ago
8 0
Acute health effects such as skin burns or acute radiation syndrome can occur when doses of radiation exceed certain levels.
kogti [31]3 years ago
8 0

Answer:

Skin burns and increasing effect of cancer.

Explanation:

Ionizing radiations are majorly produced during radioactivity process. Radioactivity is the disintegration of radioactive elements to produce energy. This energy produced are in form of ionizing radiations. Most elements that undergoes radioactivity are unstable and they produce some electromagnetic radiations like gamma rays, alpha rays and beta rays. Some of this radiations are harmful to the health and serves as threats and hazards to humans. Some of this hazards caused by this radiations includes skin burns and cancer which are due to our exposure to sources of ionizing radiations some of which are x-rays in hospitals, soil and vegetation.

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A train travels from over city to another its initial velocity is lower than its final velocity this is a example of
Anni [7]
I belive the answer is D)
4 0
3 years ago
Convection currents produce the heat in the Earth’s interior.
DaniilM [7]

Answer:

False

Explanation:

Convection currents do not produce heat. In fact, convection current are a method of transfer of heat, not of production. Convection occurs when there is a fluid which is heated from bottom, from an external source of heat (such as a pot of boiling water over a flame): the bottom part of the fluid becomes warmer, and so less dense than the colder part, therefore it starts moving up, and it is replaced by the colder parts of the fluid, which go down. Later, these colder parts become warmer, so they start going up, being replaced by new colder parts, etc... in a cycle. This is known as convection current, but it requires an external source of heat, it does not produce heat by itself.

8 0
3 years ago
Read 2 more answers
Lasers emit light of a certain frequency in one, precise direction. The light that a laser emits can be tuned to have a high fre
makkiz [27]

Answer:

An ultra intense laser is one with which intensities greater than 1015 W cm-2 can be achieved.

Explanation:

This intensity, which was the upper limit of lasers until the invention of the Chirped Pulse Amplification, CPA technique, is the value around which nonlinear effects on the transport of radiation in materials begin to appear.

Currently, the most powerful lasers reach intensities of the order of 1021W cm-2 and powers of Petawatts, PW, in each pulse. This range of intensities has opened the door for lasers to a multitude of disciplines and scientific areas traditionally reserved for accelerators and nuclear reactors, applying as generators of high-energy electron, ion, neutron and photon beams, without the need for expensive infrastructure.

8 0
3 years ago
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A kayaker needs to paddle north across a 100-m-wide harbor. The tide is going out, creating a tidal current that flows to the ea
Savatey [412]

Answer:

41.81^{\circ}

Explanation:

The tidal current flows to the east at 2.0 m/s and the speed of the kayaker is 3.0 m/s.

Let Vector \overrightarrow{OA} is the tidal current velocity as shown in the diagram.

In order to travel straight across the harbor, the vector addition of both the velocities (i.e the resultant velocity, \vec {R} must be in the north direction.

Let \overrightarrow{AB} is the speed of the kayaker having angle \theta measured north of east as shown in the figure.

For the resultant velocity in the north direction, the tail of the vector \overrightarrow {OA} and head of the vector \overrightarrow{AB} must lie on the north-south line.

Now, for this condition, from the triangle OAB

|\overrightarrow{AB}|\sin \theta=|\overrightarrow{OA}|

\Rightarrow \sin\theta=\frac{|\overrightarrow{OA}|}{|\overrightarrow{AB}|}=\frac 2 3

\Rightarrow \theta=\sin^{-1}\frac23

\Rightarrow \theta=41.81^{\circ}

Hence, the kayaker must paddle in the direction of 41.81^{\circ}  in the north of east direction.

3 0
3 years ago
How long does it take light to travel 850 km in a vacuum? Answer in ms.(Express your answer to two significant figures.)
poizon [28]

Answer:

0.002833 sec

Explanation:

Speed of light in vacuum is 3\times 10^{8}m/sec

Given distance = 850 km = 850×1000=850000 m

We have to calculate the time that light take to travel the distance 850 km

Time T=\frac{distance }{speed}=\frac{850000}{3\times 10^8}=2.833\times 10^{-3}sec

So the time taken by light to travel 850 km is 0.002833 sec

5 0
3 years ago
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