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3 years ago

Physics is really confusing...is there anyone that can show it to me?

Physics

1 answer:

coldgirl [10]3 years ago

3 0

Answer:

1.0×10³ N

Explanation:

μs is the static coefficient of friction. That's the friction that acts on a stationary (non-moving) object when being pushed or pulled.

μk is the kinetic coefficient of friction. That's the friction that acts on a moving object.

To budge the pig (while it's still stationary), we need to overcome the static friction.

F = N μs

For a non-moving object on level ground, the normal force N equals the weight.

F = mg μs

Given m = 130 kg and μs = 0.80:

F = (130 kg) (9.8 m/s²) (0.80)

F = 1019.2 N

Rounded to two significant figures, the force needed to budge the pig is 1.0×10³ N.

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State and prove bessel inequality

maria [59]

Statement :- We assume the orthagonal sequence ${{\{\phi\}}_{1}^{\infty}}$ in Hilbert space, now ${\forall \sf \:v\in \mathbb{V}}$ , the Fourier coefficients are given by:

${\quad \qquad \longrightarrow \sf a_{i}=(v,{\phi}_{i})}$

Then Bessel's inequality give us:

${\boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}$

Proof :- We assume the following equation is true

${\quad \qquad \longrightarrow \displaystyle \sf v_{n}=\sum_{i=1}^{n}a_{i}{\phi}_{i}}$

So that, ${\bf v_n}$ is projection of ${\bf v}$ onto the surface by the first ${\bf n}$ of the ${\bf \phi_{i}}$ . For any event, ${\sf (v-v_{n})\perp v_{n}}$

Now, by Pythagoras theorem:

${:\implies \quad \sf \Vert v\Vert^{2}=\Vert v-v_{n}\Vert^{2}+\Vert v_{n}\Vert^{2}}$

${:\implies \quad \displaystyle \sf ||v||^{2}=\Vert v-v_{n}\Vert^{2}+\sum_{i=1}^{n}\vert a_{i}\vert^{2}}$

Now, we can deduce that from the above equation that;

${:\implies \quad \displaystyle \sf \sum_{i=1}^{n}\vert a_{i} \vert^{2}\leqslant \Vert v\Vert^{2}}$

For ${\sf n\to \infty}$ , we have

${:\implies \quad \boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}$

Hence, Proved

5 0

2 years ago

Read 2 more answers

a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin

Daniel [21]

This question involves the concepts of Wein's displacement law and characteristic wavelength.

The blackbody temperature will be "3.22 x 10⁵ k".

<h3>WEIN'S DISPLACEMENT LAW</h3>

According to Wein's displacement law,

$\lambda_{max} T = c\\\\T=\frac{c}{\lambda_{max}}$

where,

$\lambda_{max}$ = characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
T = temperature = ?
c = Wein's displacment constant = 2.897 x 10⁻³ m.k

Therefore,

$T=\frac{2.897\ x\ 10^{-3}\ m.k}{9\ x\ 10^{-9}\ m}$

T = 3.22 x 10⁵ k

Learn more about characteristic wavelength here:

brainly.com/question/14650107

7 0

3 years ago

. Mass 1 has a momentum of 20 kg*m/s. Mass 2 has a momentum of 50 kg*m/s.

sesenic [268]

Answer:

55kgm/s

Explanation:

3 0

3 years ago

What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?

sveta [45]

Momentum = (mv).
<span>(2110 x 24) = 50,640kg/m/sec. truck momentum. </span>
<span>Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec</span>

8 0

3 years ago

1. George is traveling to Boston from Springfield. Springfield is 144

denpristay [2]

Answer:

48 kilometers per hour

Explanation:

144/3 = 48 km/h

3 0

2 years ago