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andrew-mc [135]
3 years ago
10

What is the nuclear binding energy for uranium-238 in joules? Assume the following:What is the nuclear binding energy for uraniu

m-238 in joules? Assume the following:
Mass defect = 3.2008 x 10-27 kilograms
Use E = mc2, with c = 3 x 108 m/s



0.28807 x 10-12 joules



2.8807 x 10-12 joules



2.8807 x 10-10 joules



2.8807 x 10-8 joules



3.2008 x 1027 joules
Chemistry
2 answers:
ruslelena [56]3 years ago
4 0
Assume <span>the following: </span><span>Mass defect = 3.2008 x 10-27 kilograms</span><span>
</span><span>Use E = mc2, with c = 3 x 108 m/s
</span>
The nuclear binding energy for uranium-238 in joules is 2.8807 x 10-8 joules. 
serg [7]3 years ago
3 0

Answer:

the answer is D for Plato

Explanation:

The nuclear binding energy for uranium-238 in joules is 2.8807 x 10-8 joules.

hopes this helps

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under certain water​ conditions, the free chlorine​ (hypochlorous acid,​ hocl) in a swimming pool decomposes according to the la
ivolga24 [154]

Answer:

1.7 ppm

Explanation:

Original amount N' = 2.6 ppm

time to testing t = 24 hr

final amount N = 2.1 ppm

Using exponential inhibited decay, we have

N = N'e^(-kt)

Where

N is the new reading

N' is the original reading

t is the decay time

k is the decay constant

Substituting, we have

2.1 = 2.6 x e^(-k x 24)

2.1 = 2.6 x e^(-24k)

0.808 = e^(-24k)

We take the natural log of both sides of the equation

Ln 0.808 = Ln (e^(-24k))

-0.213 = - 24k

K = 0.213/24 = 0.00886

After 48 hrs, the reading of free chlorine will be

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5 0
3 years ago
Which of the following could you do to increase the strength of an electromagnet? decrease the number of windings decrease the e
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8 0
3 years ago
Read 2 more answers
fills a 500.mL flask with 3.6atm of carbon monoxide gas and 1.2atm of water vapor. When the mixture has come to equilibrium she
enot [183]

Answer:

The answer to the question is

The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits

Explanation:

To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure

At the first trial the mixture contains

3.6 atm CO

1.2 atm H₂O (g)

Total pressure = 3.6+1.2= 4.8 atm

which gives

3.36 atm CO

0.96 atm H₂O (g)

0.24 atm H₂ (g)

That is

CO+H₂O→CO(g)+H₂ (g)

therefore the mixture contained

0.24 atm CO₂ and the total pressure =

3.36+0.96+0.24+0.24 = 4.8 atm

when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂

At equilibrium we have 0.24*0.24/(3.36*0.96) = 0.017857

adding 1.8 atm CO gives 4.46 atm hence we have

 (0.24+x)(0.24+x)/(4.46-x)(0.96-x) = 0.017857

which gives x = 0.031 atm or x = -0.6183 atm

Dealing with only the positive values we have the pressure of carbon dioxide = 0.24+0.03 = 0.27 atm

7 0
3 years ago
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