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andrew-mc [135]
3 years ago
10

What is the nuclear binding energy for uranium-238 in joules? Assume the following:What is the nuclear binding energy for uraniu

m-238 in joules? Assume the following:
Mass defect = 3.2008 x 10-27 kilograms
Use E = mc2, with c = 3 x 108 m/s



0.28807 x 10-12 joules



2.8807 x 10-12 joules



2.8807 x 10-10 joules



2.8807 x 10-8 joules



3.2008 x 1027 joules
Chemistry
2 answers:
ruslelena [56]3 years ago
4 0
Assume <span>the following: </span><span>Mass defect = 3.2008 x 10-27 kilograms</span><span>
</span><span>Use E = mc2, with c = 3 x 108 m/s
</span>
The nuclear binding energy for uranium-238 in joules is 2.8807 x 10-8 joules. 
serg [7]3 years ago
3 0

Answer:

the answer is D for Plato

Explanation:

The nuclear binding energy for uranium-238 in joules is 2.8807 x 10-8 joules.

hopes this helps

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25mL if water as the highest average of the kinetic energy
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3 years ago
Open the Balancing Chemical Equations interactive and select Introduction mode. Then choose Separate Water. Adjust the coefficie
aleksklad [387]
<h2>H_2O  + H_2 + O_2</h2>

Explanation:

1. Water decomposition

  • Decomposition reactions are represented by-

       The general equation: AB → A + B.

  • Various methods used in the decomposition of water are -
  1. Electrolysis
  2. Photoelectrochemical water splitting
  3. Thermal decomposition of water
  4. Photocatalytic water splitting
  • Water decomposition is the chemical reaction in which water is broken down giving oxygen and hydrogen.
  • The chemical equation will be -

        H_2O  + H_2 + O_2

Hence, balancing the equation we need to add a coefficient of 2 in front of H_2O on right-hand-side of the equation and  2 in front of H_2 on left-hand-side of the equation.

     ∴The balanced equation is -

       2 H_2O → 2 H_2 + O_2

2. Formation of ammonia

  • The formation of ammonia is by reacting nitrogen gas and hydrogen gas.

      N_2 + H → NH_3

Hence, for balancing equation we need to add a coefficient of 3 in front of hydrogen and 2 in front of ammonia.

   ∴The balanced chemical equation for the formation of ammonia gas is as  follows -

     N_2+3H→ 2NH_3.

  • When 6 moles of N_2 react with 6 moles ofH_2 4 moles of ammonia are produced.

5 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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attashe74 [19]
<h2>The answer is option b "free energy is zero"</h2>

Explanation

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  • The reaction that has zero free energy occurs when the free energy of both reactants and the products are same hence the rate of formation of products and reactants are equal.
  • Therefore, when reactants and products are being formed at an equal rate the free energy is zero.
3 0
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In a chemical reaction, the final amount of the products is determined by the _______.
lana66690 [7]

Answer: I believe it is B

Explanation:

because it states that a chemical compound always contains exactly the same proportion of elements by mass

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