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Sati [7]
3 years ago
15

A student has 10 mL of a solution that might contain any or all of the following cations at 0.01 M concentrations: Mn2+, Ba2+, A

g+ , and Cu2+. Addition of 10 mL of 1 M HCl causes a precipitate to form. After the precipitate is filtered off, 1 M H2SO4 is added to the filtrate and another precipitate forms. What is the second precipitate
Chemistry
1 answer:
Ivanshal [37]3 years ago
7 0
<span>For the answer to the question above,
Addition of HCl causes a precipitate to form: 
Ag+ & Cl- -- AgCl a white ppt 


H2SO4 is added to the supernate another precipitate forms: 
Ba+2 & SO4-2 --> BaSO4 a white ppt 


a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed: 
no Mn+2 & no Cu+2 which would have ppt as hydroxides</span>
I hope this helps you.
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The volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.

<h3>How to calculate volume?</h3>

The volume of a given mass of gas can be calculated using the following formula:

PV = nRT

Where;

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According to this question, 0.98 moles of oxygen gas at 275 k contains a pressure of 2.0 atm. The volume is calculated as follows:

2 × V = 0.98 × 0.0821 × 275

2V = 22.13

V = 11.06L

Therefore, the volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.

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