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Makovka662 [10]
4 years ago
5

A 2.8-kg physics cart is moving forward with a speed of 45 cm/s. A 1.9-kg brick is dropped from rest and lands on the cart. The

cart and brick move together across the horizontal surface. Assume an isolated system. what equation do i use to figure out the the final valocity
Physics
1 answer:
anzhelika [568]4 years ago
4 0

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Which of the following statements about a metal wire in the steady state are true? Select all that apply.
nata0808 [166]

Answer:

Options: 1, 3, 5, 7, 8

Explanation:

In steady state at the point when the current at each point in the circuit is  

consistent (doesn't change with time).  

  • In numerous viable circuits, the steady state is accomplished in a brief period of time.
  • In the steady state, the charge (or current) streaming into any point in the circuit needs to equivalent the charge (or current) streaming out which is  Kirchhoff's Node or Current law.
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An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c
KiRa [710]

Acceleration can be defined as the change of speed in an instant of time, that is

a = \frac{v_f-v_i}{\Delta t}

Here,

v_f = Final velocity

v_i = Initial velocity

\Delta t = Change in time

From this expression we will calculate the requested values replacing the variables in each of the given terms

PART A) The values under this condition are:

v_f = 5.3m/s

v_i = 15m/s

\Delta t = 10.4s

Replacing,

a = \frac{5.3m/s-(15m/s)}{10.4s}

a = -0.93m/s^2

PART B ) The values under this condition are:

v_f = -15m/s

v_i = -5.3m/s

\Delta t = 10.4

Replacing,

a = \frac{-(15m/s)-(-5.3m/s)}{10.4s}

a = -0.93m/s^2

Therefore the acceleration in the second time interval is -0.93m/s^2

PART C) The values under this condition are:

v_f = -15m/s

v_i = 15m/s

\Delta t = 10.4

Replacing,

a = \frac{-15m/s-(15m/s)}{10.4s}

a = -2.9m/s^2

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In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0800 s, during which
Elena-2011 [213]
The initial velocity of the ball is 0. Applying:
v = u + at
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v = 18.3 m/s

a)
Vx = Vcos(∅)
Vx = 18.3cos(52.3)
Vx = 11.2 m/s

b)
Vy = Vsin(∅)
Vy = 18.3sin(52.3)
Vy = 14.5 m/s
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3 years ago
What pressing problem did the invention of the cotton gin solve?
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