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Flauer [41]
3 years ago
5

Why does the radius of an atom decrease as you go across (from left to right) a period on the periodic table?

Chemistry
2 answers:
saveliy_v [14]3 years ago
7 0
The most reasonable anwer would be B
Grace [21]3 years ago
3 0
Answer is D) <span>because you are adding positively charged protons, which pull in the outer electrons
</span>
The radius of an atom decreases because the atomic number, or number of protons is increasing. This not only pulls in the outer electrons due to the increasing positive charge, but also increases the mass of the atom, which has the effect of drawing electrons toward the nucleus. 
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For every action there is an equal and opposite reaction is known as? *
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Answer:

Newton's third law

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The diagram shows Niels Bohr’s model of an atom.
PtichkaEL [24]

Answer:

Energy is absorbed, and an emission line is produced.

Explanation:

Electrons are present and revolving continuously in the orbits that are present around the nucleus. The energy of electron are fixed and unable to move to other orbits due to the strong attractive force of the proton which is present in the nucleus of the atom. If the electron wants to jump from the first energy level to the second energy level, so the electron has to absorb enough energy which can overcome the attractive force of proton.

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List the following elements in order from lowest boiling point to highest
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Answer:

Aluminum lodide - 680 degrees

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hope this helps:)

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2 years ago
List the number of protons, neutrons, and electrons in . B C<br> 6
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4 0
3 years ago
At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +
Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(c) A ( g ) + B ( g ) ⟶ C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

4 0
2 years ago
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