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Sergeeva-Olga [200]
3 years ago
10

A pycnocline is a boundary between changing regions of which of the following properties? What about a thermocline?

Physics
2 answers:
seropon [69]3 years ago
5 0
The answer is <span>temperature, salinity
Hope this helps. :)</span>
kotegsom [21]3 years ago
4 0

Answer:

temperature, salinity

Explanation:

In oceanography, pycnocline is the layer of the water column where a rapid change in vertical density gradient occurs. This increase in density with increasing depth is generally more intense in low latitude regions, as at high latitudes the density has little variation with depth. The term pycnocline is analogous to the terms halocline (intense vertical salinity gradient) and thermocline (intense vertical temperature gradient). Generally the three features occur at the same depths, typically between 300 and 1000 m below the ocean surface. Pycnocline is the result of the combination of thermocline and halocline, as temperature and salinity influence the density of seawater. The relationship between these three factors (temperature, salinity and density) conditions the distribution of water bodies in the ocean.

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The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between t
Radda [10]

Answer:

a)F = 6816.5680 N

b) F' = 0 N

c)F''=28195.5N

Explanation:

Magnitude of charges M=1.6\muC

Distance d=2.6

Generally the equation for  Net Force is mathematically given by

For First Drawing

F =\frac{ k q^2}{d^2}+\frac{k q^2}{d^2}  

F =\frac{2* 9*10^9* (1.6*10^-6)^2}{ (2.6*10^-3^2}

F = 6816.5680 N

For second Drawing

F' =\frac{ k q^2}{d^2 }-\frac{ k q^2}{ d^2}  

F' = 0 N

For Third Drawing

F'' =\frac{ k q^2}{d^2} * \sqrt (2)

F'' = 9*10^9* (6.4*10^-6)^2 * \frac{\sqrt(2)}{(4.3*10^-3)^2}

F''=28195.5N

4 0
3 years ago
1.
xz_007 [3.2K]

Answer: A. All of the answers are correct.

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Read 2 more answers
if you crash your car how could you decrease the damage to you or the car using the concept of impulse
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Explanation:

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3 years ago
a tms (transcranial magnetic stimulation) device creates very rapidly changing magnetic fields. the field near a typical pulsed-
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Part B : 4764 Amperes.

Given Data :  

Field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs.

Axis of his 2.1-cm-diameter wedding band is parallel to the field.

Part A :

induced emf = rate of change of magnetic flux

= d (B A )/dt

= A dB/dt

= { π (2.1 x 10^-2 / 2)^2) (2.5) } / (200 x 10^-6)

E = 4.33 Volt

Part B :

R = rho L / A

R = { (6.2 x 10^-8) ( π x 0.021) } / (4.5 x 10^-6)

R = 9.10 x 10^-4 Ohm

We know, (I = V/ R)

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What exactly is the function of TMS?

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Find more on TMS at : brainly.com/question/13851741

#SPJ4

➤ Although your question isn't complete, I may have assumed that you were referring to this specific question.

The complete question is :

A TMS (transcranial magnetic stimulation) device creates very rapidly changing magnetic fields. The field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs. Suppose a technician holds his hand near the device so that the axis of his 2.1-cm-diameter wedding band is parallel to the field.

Part A: What emf is induced in the ring as the field changes? Express your answer to two significant figure E= ___ unit_

Part B: If the band is made of a gold alloy with resistivity 6.2×10−8Ω⋅m and has a cross-section area 4.5 mm2 , what is the induced current? Express your answer to two significant figures and include the appropriate units. I= ___ units__

6 0
1 year ago
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