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wel
3 years ago
7

which phrase best defines erosion. chemically breaking rocks apart, moving bits of rock from place to place , cementing bits of

rocks together, or physically breaking rocks apart
Physics
2 answers:
mina [271]3 years ago
4 0
Physically breaking rocks apart i think
i hope this helps
monitta3 years ago
4 0
I also think it's the last one.
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Using a common metric ruler, you measure the separation distance between two Al spheres from center to center to be 2.3 cm. What
Reptile [31]

Answer: 0.5 mm

Explanation: The smallest division that a common ruler has is 1 mm so any measurement taken is approximately accurate to a mm.

Uncertainty of any measuring instrument is the inaccuracy or lost of precision that occur due to its less divisions in an instrument

Uncertainty= Least Count /2

Uncertainty= 1 mm /2

Uncertainty= 0.5 mm

it means that measurement can be 2.3cm ± 0.5mm

8 0
3 years ago
A sound wave produced by a chime 515 m away is heard 1.50 s later. What is the speed of the sound in the air?
aliina [53]

Answer:

the speed of the sound in the air is 343.3 m/s

Explanation:

The computation of the speed of the sound in the air is shown below:

As we know that

Speed = Distance ÷ time

So, here speed be 515 m

And, the time is 1.50 seconds

So, the speed of the sound is

= 515 m ÷ 1.50 seconds

= 343.3 m/s

hence, the speed of the sound in the air is 343.3 m/s

6 0
3 years ago
Explain two scenarios where a large truck can have the same momentum as a small car.
KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0
3 years ago
A 5.00-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
mezya [45]

Answer:A7.50kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of2.30s. Find the force constant of the spring.

N/m

Explanation:

5 0
3 years ago
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
jeyben [28]

Question:

Assumptions

Voltage of battery = 24 V

Resistance on the right,20Ω parallel to 10 Ω resistor

Answer:

For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω

Explanation:

We note that the switch in the assumption is on the same line as the 20 Ω resistor.

With a voltage of 24 V, and the switch closed, we have;

Total resistance =  \frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega

Current out of voltage, I  = Voltage/(total resistance)

= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A

Therefore, with the switch opened, we get

Resistance on the right = Initial total resistance =  \frac{20}{3} \Omega

Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.

6 0
3 years ago
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