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defon
3 years ago
12

An object is dropped from a height h. during the final second of its fall, it traverses a distance of 41.2 m. what was h?

Physics
1 answer:
Leya [2.2K]3 years ago
3 0
41.2 = h-1/2g(t-1)^2 
<span> {-h = -1/2gt^2-1/2g+g*t-41.2 
</span><span> {h = 1/2gt^2 
</span><span> summing them up 
</span><span> 0 = -1/2g+g*t-41.2 
</span><span> 41.2 +4.9 = g*t 
</span><span> t = 46.1/9.8 = 4.70 sec 
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>
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