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3 years ago

An object is dropped from a height h. during the final second of its fall, it traverses a distance of 41.2 m. what was h?

1 answer:

3 0

41.2 = h-1/2g(t-1)^2
 {-h = -1/2gt^2-1/2g+g*t-41.2
 {h = 1/2gt^2
 summing them up
 0 = -1/2g+g*t-41.2
 41.2 +4.9 = g*t
 t = 46.1/9.8 = 4.70 sec
 h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m

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1 year ago

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Explanation:

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2 years ago

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3 years ago