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Marizza181 [45]
3 years ago
12

G a person of mass 100 kg is riding an elevator which was initially moving up with a velocity of 3 m/s. over a distance of 4 m t

he elevator slows down to 1 m/s. find the "apparent" mass of the person during that time (as the elevator slows down).
Physics
1 answer:
andriy [413]3 years ago
3 0
E=mc² where c is speed of the light
3 m/s more andmore less than speed of the light. So mass of the person still 100 kg
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Answer:

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Explanation:

We are given that

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