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Marizza181 [45]

2 years ago

12

G a person of mass 100 kg is riding an elevator which was initially moving up with a velocity of 3 m/s. over a distance of 4 m t

he elevator slows down to 1 m/s. find the "apparent" mass of the person during that time (as the elevator slows down).

1 answer:

andriy [413]2 years ago

3 0

E=mc² where c is speed of the light
3 m/s more andmore less than speed of the light. So mass of the person still 100 kg

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