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Marizza181 [45]
3 years ago
12

G a person of mass 100 kg is riding an elevator which was initially moving up with a velocity of 3 m/s. over a distance of 4 m t

he elevator slows down to 1 m/s. find the "apparent" mass of the person during that time (as the elevator slows down).
Physics
1 answer:
andriy [413]3 years ago
3 0
E=mc² where c is speed of the light
3 m/s more andmore less than speed of the light. So mass of the person still 100 kg
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24 POINTS!!!!!!!!!!!!!!!
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Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
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Kinetic Energy (Final One) = 1/2 mv²
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Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

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