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muminat
3 years ago
12

Lead has a density of 11.3 g/cm3. if you have 1.0 kg of lead, what is the volume in cubic centimeters (cm3)? remember to select

an answer with the correct number of significant figures.
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
4 0
In this case, you are given the density( 11.3g/cm3) and the weight (1kg) of the lead. You are asked to find the volume of the lead.
To find volume you need to divide the weight with the density. It would be:
volume= weight/density
volume = 1kg x (1000 gram/kg) / (11.3g/cm3)= 88.495 cm3

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8 0
3 years ago
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What is the ph of a soft drink in which the major buffer ingredients are 6.6 g of nah2po4 and 8.0 g of na2hpo4 per 355 ml of sol
Alex777 [14]
The Relative Formula Mass of NaH2PO4 is 120 g/mol
Therefore, the number of moles = 6.6/120
                                                   = 0.055 moles of NaH2PO4 which is also equal to the number of moles of H2PO4.
[H2PO4-] = Number of moles oof H2PO4-/Volume of the solution in L
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Na2HPO4 undergoes complete dissociation as follows;
Na2HPO4 (aq)= 2Na+ (aq) + HPO4^2- (aq)

1 mole of Na2HPO4 = 142 g/mol
Therefore; number of moles = 8.0/142
                                             = 0.0563 moles
 [HPO4 ^-2] is given by no of moles HPO4^2- /volume of the solution in L
     = 0.0563/(355×10^-3)
     =  0.1586 M
Both H2PO4^2- and HPO4^2- are weak acids the undergoes partial dissociation 
Ka of H2PO4- = 6.20 × 10^-8
 [H+] =Ka*([H2PO4-]/[HPO4(2-)]
        = (6.20 ×10^-8)×(0.155/0.1586)
        = 6.059 ×10^-8 M
pH = - log[H+]
     = - log (6.059×10^-8)
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Explanation

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So the reactants are usually written in the left side of the chemical equation whereas on the right the products are written.

Both the sides are linked by a single headed arrow mark.

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