Given Information:
Number of turns = N = 1130 turns
Length of solenoid = L = 0.430 m
Magnetic field = B = 1.0x10⁻⁴ T
Required Information:
Current = I = ?
Answer:
I = 0.0302 A
Explanation:
The current flowing in the solenoid winding can be found using
I = BL/μ₀N
Where μ₀ is the permeability of free space, N is the number of turns, B is the magnetic field and L is the length of solenoid
I = 1.0x10⁻⁴*0.430/4πx10⁻⁷
*1130
I = 0.0302 A
or
I = 30.28 mA
To calculate the ideal mechanical advantage for an inclined plane, divide th length of the incline by the height of the incline.
Therefore; IMA = L/h
L= 3.0 m, while h =1.0 m
IMA = 3/1
= 3
Therefore the IMA of the ramp is 3
This means the ramp increases the force that is being exerted by 3 times.
When the child is moving, he/she has kinetic energy. For just a brief second before they move the other way, the child is not moving, but they have gravitational potential energy.
The child may need a push from time to time because friction with the air causes loss of energy.
Average acceleration = (change in speed) / (time for the change) .
Change in speed = (ending speed) - (beginning speed)
= (9.89 miles/hour) - (2.35 yards/second) = 26,839.2 ft/hr
Acceleration = (26,839.2 ft/hr) / (4.67 days) = 2,873.58 inch/hour²
Explanation:
S =ut + 1/2at^2
S = 0×6.5 + (1/2 × 9.54) × 6.5^2
S =0 + 4.77 ×42.25
S=201.5m