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ElenaW [278]
3 years ago
7

Each astronaut produces 8.8 x 10^2 grams of CO2 per day that must be removed from the air on the shuttle if typical shuttle miss

ion is 9 days and the shuttle can carry 3.5 x 10^4 grams LiOH what is the maximum number of people the shuttle can safely carry for one mission?
Chemistry
2 answers:
Ksju [112]3 years ago
7 0

Answer:

4 astronauts.

Explanation:

iris [78.8K]3 years ago
5 0
M₀(CO₂)=8.8*10² g
m(LiOH)=3.5*10⁴ g
x=9 d

2LiOH + CO₂ = Li₂CO₃ + H₂O

m(CO₂)=M(CO₂)m(LiOH)/2M(LiOH)

N=m(CO₂)/xm₀(CO₂)=M(CO₂)m(LiOH)/{2M(LiOH)xm₀(CO₂)}

N=44.01*3.5*10⁴/{2*23.95*9*8.8*10²}=4

The maximum number of people is 4.

It is also possible the reaction:
Li₂CO₃ + CO₂ + H₂O = 2LiHCO₃


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Waters freezing point in Celsius is 0 and 273.15 Kelvin (or 273 rounded to a whole number.

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3 years ago
In the equation below, identify the Brønsted-Lowry acid, the Brønsted-Lowry base, conjugate acid, conjugate base.
AnnyKZ [126]

Answer:

Explanation:

Your B-L Acid is a proton (Hydrogen, H+) donor, and your B-L base is a proton acceptor. This means that the base will take a hydrogen from your acid. NO2- is a B-L base, and you can tell it is a base by the negative charge it possesses. This means that it has a lone pair that wants to grab one of the hydrogens from NH4+, the B-L acid. In scientific words, the NO2- is a nucleophile and NH4+ is an electrophile. The result of NO2- grabbing that hydrogen from NH4+ is that NO2- becomes HNO2 (your conjugate acid) and and NH4+ becomes NH3 (you conjugate base). Basically, any time a B-L acid loses a proton, its equal product will be its conjugate base, and any time a B-L base gains a proton, its equal product will be its conjugate acid.

I hope this helped explain the concept behind Bronsted-Lowry acids and bases! Good luck with your class and please don't forget to give a positive rating! :-)

7 0
3 years ago
An endothermic process is one in which heat is ________ from the surroundings. (2 points)
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Hope it helps ^-^

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2 years ago
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Ira Lisetskai [31]

Answer:

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8 0
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Orlov [11]

Answer:

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After prolonged exposure to the<em> hypotonic</em> solution, the flexible cell membrane swells and eventually bursts.

A gram positive bacterial cell has a rigid cell wall and a cell membrane. When exposed to a <em>hypotonic</em> solution, water flows from the outside environment to the interior of the cell by osmosis through the cell wall and membrane. The rigid cell wall of the bacterial cell however, contains the swelling and prevents the cell from bursting.

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