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ASHA 777 [7]
3 years ago
7

The gravitational self potential energy of a solid ball of mass density ρ and radius R is E. What is the gravitational self pote

ntial energy of a ball of mass density ρ and radius 2R in terms of E?
Physics
1 answer:
Alenkasestr [34]3 years ago
8 0
It will be
E = mgh.
where h and g are constant thus
m can be written as 4/3πr^3*density
E = 4/3πr^3* density
E? = 4/3π(2R)^3* density
= 4/3π8r^3
thus the e will be 4/3π8r^3* density/4/3πr^3*density nd thus you get 8E ..
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how come if you jump in a train you will land in the same spot but if you jump on top of the train you won't? i tried to make it
soldier1979 [14.2K]

Answer:

Well, it has to do something with the force of the train. It's pulling you, a force of gravity

However jumping off results in a different sort of energy, the train know is moving farther away as you jump down. So you end up in a different place

Explanation:

3 0
3 years ago
The group one metals are called alkaline metal and group two metals are called alkaline earth metal why?​
Ilya [14]

Answer:

The group one element are called alkali because when they dissolved in water they form alkaline solutions

5 0
2 years ago
1 Calculate the size of the quantum involved in the excitation of (a) an electronic motion of frequency 1.0 × 1015 Hz, (b) a mol
torisob [31]

Answer: a) E= 6.63x10^-19J

E= 3.97×10^2KJ/mol

b) E = 3.31×10^-19J

E= 18.8×10^4 KJ/mol

C) E = 1.32×10^-33J

E= 8.01×10^-10KJ/mol

Explanation:

a) E = h ×f

h= planks constant= 6.626×10^-34

E=(6.626×10^-34)×(1.0×10^15)

E=6.63×10^-19J

1mole =6.02×10^23

E=( 6.63×10^-19)×(6.02×10^23)

E=3.97×10^2KJ/mol

b) E =(6.626×10^-34)/(1.0×10^15)

E=3.13×10^-19J

E= 3.13×10^-19) ×(6.02×10^23)

E= 18.8×10^3KJ/MOL

c) E= (6.626×10^-34) /0.5

E= 1.33×10^-33J

E= (1.33×10^-33) ×(6.02×10^23)

E= 8.01×10^-10KJ/mol

8 0
4 years ago
An astronaut weighs 8.00x10^2 newtons on the surface of Earth. What is the weight of the astronaut 6.37x10^6 meters above the su
Orlov [11]
800/2^2=2.oo10^10^2N
8 0
4 years ago
Bird bones have air pockets in them to reduce their weight. This also gives them an average density significantly less than that
mixas84 [53]

Answer:

mas of water displaced = 41.4 g

Explanation:

Weight in air = True weight = 45 g

Apparent weight = 3.6 g

Apparent weight = True weight - Buoyant force

Buoyant force = 45 g - 3.6 g = 41.4 g

Weight of water displaced = Buoyant force

Weight of water displaced = 41.4 g dyne

mas of water displaced = 41.4 g

8 0
3 years ago
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