D

True or False? In the electron flow theory, electrons flow from the positively charged body to the negatively charged body.

kobusy [5.1K]

I think it's false because the theory states that electrons flow from negative to positive. Since electrons are negatively charged, it follows that they are attracted by positively charged bodies and repelled by negatively charged bodies.

3 0

3 years ago

Read 2 more answers

1.00-L insulated bottle is full of tea at 90.08°C. You pour out one cup of tea and immediately screw the stopper back on the bot

liberstina [14]

Answer:

T_{f} = 90.07998 ° C

Explanation:

This is a calorimetry process where the heat given by the Te is absorbed by the air at room temperature (T₀ = 25ºC) with a specific heat of 1,009 J / kg ºC, we assume that the amount of Tea in the cup is V₀ = 100 ml. The bottle being thermally insulated does not intervene in the process

Qc = -Qb

M $c_{e_Te}$ (T₁ - $T_{f}$ ) = m $c_{e_air}$ (T_{f}-T₀)

Where M is the mass of Tea that remains after taking out the cup, the density of Te is the density of water plus the solids dissolved in them, the approximate values are from 1020 to 1200 kg / m³, for this calculation we use 1100 kg / m³

ρ = m / V

V = 1000 -100 = 900 ml

V = 0.900 l (1 m3 / 1000 l) = 0.900 10⁻³ m³

V_air = 0.100 l = 0.1 10⁻³ m³

Tea Mass

M = ρ V_te

M = 1100 0.9 10⁻³

M = 0.990 kg

Air mass

m = ρ _air V_air

m = 1.225 0.1 10⁻³

m = 0.1225 10⁻³ kg

(m c_{e_air} + M c_{e_Te}) T_{f}. = M c_{e_Te} T1 - m c_{e_air} T₀

T_{f} = (M c_{e_Te} T₁ - m c_{e_air} T₀) / (m c_{e_air} + M c_{e_Te})

Let's calculate

T_{f} = (0.990 1100 90.08– 0.1225 10⁻³ 1.225 25) / (0.1225 10⁻³ 1.225 + 0.990 1100)

T_{f} = (98097.12 -3.75 10⁻³) / (0.15 10⁻³ +1089)

T_{f} = 98097.11 / 1089.0002

T_{f} = 90.07998 ° C

This temperature decrease is very small and cannot be measured

3 0

3 years ago

6. True or False? Common materials used in media

erastova [34]

Answer:

its false

i think it is right

4 0

3 years ago

g Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in bin

Phoenix [80]

Answer:

The solution is written in Python

binary = ""
decimal = 13
quotient = int(decimal / 2)
remainder = decimal % 2
binary = str(remainder) + binary
while(quotient >0):
decimal = int(decimal / 2)
quotient = int(decimal / 2)
remainder = decimal % 2
binary = str(remainder) + binary
print(binary)

Explanation:

Firstly, we declare a variable binary and initialize it with an empty string (Line 1). This binary is to hold the binary string.

Next, we declare variable decimal, quotient and remainder (Line 2-4). We assign a test value 13 to decimal variable and then get the first quotient by dividing decimal with 2 (Line 3). Then we get the remainder by using modulus operator, % (Line 4). The first remainder will be the first digit joined with the binary string (Line 5).

We need to repeat the process from Line 3-5 to get the following binary digits. Therefore create a while loop (Line 7) and set a condition that if quotient is bigger than 0 we keep dividing decimal by 2 and calculate the quotient and remainder and use the remainder as a binary digit and join it with binary string from the front (Line 9-11).

At last, we print the binary to terminal (Line 13).

4 0

4 years ago

A fluid has a viscosity of 13 P and a specific gravity of 0.94. Determine the kinematic viscosity of this fluid in units of ft²/

OlgaM077 [116]

Answer:

kinematic viscosity is 0.0149 ft²/s

Explanation:

given data

specific gravity S = 0.94

density ρ = 0.94 × 1000

viscosity μ = 13 Poise = 1.3 Pa-sec

we know 1 poise = 0.1 pas

to find out

kinematic viscosity

solution

we will apply here Kinematic viscosity formula that is

kinematic viscosity = $\frac{\mu}{\rho}$ ..................1

put here value in equation 1

and here ρ is density and μ is viscosity

kinematic viscosity = $\frac{1.3}{0.94*1000}$

kinematic viscosity = 1.382978 × $10^{-3}$ m³/s

so kinematic viscosity is 0.0149 ft²/s

3 0

3 years ago