I attached a Diagram for this problem.
We star considering the system is in equlibrium, so
Fm makes with vertical
Fm makes 70 with vertical
Applying summatory in X we have,
We know that W is equal to
Substituting,
<em>For the second part we know that the reaction force Fj on deltoid Muscle is equal to Fm, We can assume also that</em>
<span>Yes, there are! r1 and r2 are numbers. The volume of the hollow shell is 4 π 3 ( r 3 1 − r 3 2 ) 4π3(r13−r23). Now multiply by ρ to get the mass.</span>
V₀=6.35*4=25.4 m/s the speed of the when car enters into main speedway
S=V₂t
S=73t - distance of the second car
S=V₀t+at²/2
S=25.4t+6.35t²/2 - distance of the first car
6.35t²/2+25.4t=73t
t*(3.175t-47.6)
3.175t=47.6
t=14.99 s
14.99 s is required for the first car to catch the second
Answer:
a) the distance the ball moves up the ramp is approximately 9.35 meters
b) the tme required for the ball to return to the girls' hands is 6.34 seconds
Explanation:
The movement of the ball can be describe by a rectilinear movement with constant (negative) acceleration of 0.19 g = 1.862 m/s^2
Therefore the kinematic equations for the case the girl launches the ball at 5.9 m/s, we can write:
We use the second equation above to find the time it takes for the velocity to reduce to zero (and start the movement back down the ramp), and then use the time found to calculate the distance;
We use this time to find the distance the ball moves up the ramp:
so the distance the ball moves up the ramp is approximately 9.35 meters
The ball will return to the hands of the girl in the double of the time it took to reach the max distance, that is 2 times 3.17 sec = 6.34 sec
Answer:
A. The project's energy costs will decrease
Explanation:
Since the project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow for on-site renewable energy.
Hence, the project's energy costs will decrease very well because it's implementing both of these strategies;
- Area with demand-response program.
- On-site renewable energy.