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Pachacha [2.7K]
3 years ago
9

Congugar verbos en primera persona del singular

Physics
1 answer:
stira [4]3 years ago
3 0
This is Spanish !!!!
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Scientists earlier believed that the lowest measurable temperature is the freezing point of ice. However, modern scientists beli
Leni [432]

<span> The statement that best accounts for these different opinions is: scientists propose contradictory ideas to include all possibilities. This statement refers to the scientific method, that is a set of different techniques for investigating phenomena and gaining new knowledge that can improve or correct the previous one. As a result, analysis based on contradicting opinions leads to the progress in scientific sphere.</span>

7 0
3 years ago
A 2 kg ball if at rest. If the ball accelerates to 20 m/s, what is the change in momentum?
katrin [286]

Answer:

change in momentum

20m/s x2=40kg/m

4 0
3 years ago
An object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration wou
Flauer [41]
F has direct relation with a
then doubling F cause acc. to get double i:e 6×2=12
5 0
3 years ago
A flatbed truck is carrying an 800-kg load of timber that is not tied down. The maximum friction force between the truck bed and
ycow [4]

Answer:

Acceleration a ≤ 3 m/s^2

the greatest acceleration that the truck can have without losing its load is 3 m/s^2

Explanation:

For the truck to accelerate without losing its load.

Acceleration force of truck must be less than or equal to the maximum friction force between the truck bed and the load.

Fa ≤ F(friction)

But;

Fa = mass × acceleration

Fa = ma

ma ≤ F(friction)

a ≤ (F(friction))/m ......1

Given;

Fa = mass × acceleration

Fa = ma

mass m = 800 kg

F(friction) = 2400 N

Substituting the given values into equation 1;

a ≤ F(friction)/m

a ≤ 2400N/800kg

a ≤ 3 m/s^2

the greatest acceleration that the truck can have without losing its load is 3 m/s^2

4 0
3 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = \frac{F_{1} }{4} = \frac{27.2}{4} = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0
3 years ago
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