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Vitek1552 [10]
3 years ago
15

What is the equivalent mass of HBr in a complete neutralization reaction?

Chemistry
1 answer:
shusha [124]3 years ago
6 0
Because it is a monoprotic acid equivalent mass = molar mass
You might be interested in
One peanut M&M weighs approximately 2.33 g.
Sphinxa [80]

Answer:

There are 23076 peanut M&M's in 53.768 kg of M&M's.

Explanation:

First we <u>convert 53.768 kg into g</u>:

  • 53.768 kg * 1000 = 53768 g

Then we <u>divide the total mass of M&M's by the mass of one peanut M&M,</u> in order to calculate the answer:

  • 53768 g / 2.33 g = 23076

So there are 23076 peanut M&M's in 53.768 kg of M&M's.

3 0
2 years ago
The molecular mass of propane-1,2-diol is 76.1 amuamu . Calculate the molecular mass of propane-1,3-diol, an isomer of propane-1
sashaice [31]

Answer:

76.1 amu

Explanation:

Let us recall that isomers refer to two different compounds with the same molecular formula but different atom to atom connectivity and different chemical properties. When two compounds are isomers, we can essentially represent them with exactly the same molecular formula.

Now propane-1,2-diol and propane-1,3-diol are both represented by the molecular formula C3H8O2 since they are isomers of each other. When two compounds have the same molecular formula, they must essentially have the same molecular mass. Hence the molecular mass of propane-1,3-diol is also 76.1 amu.

8 0
3 years ago
Read 2 more answers
HURRY PLEAS!!!!!!!!!!!!!!!!!!!!
mixas84 [53]
D. action force and reaction forces are stated in his law
8 0
3 years ago
Read 2 more answers
A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %
kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and y_{C-6} and y_{N_2} are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Q=-40036+(-672.21)=-40708.21J

Finally we convert this result to kJ:

Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ

Learn more:

  • brainly.com/question/25475410
  • brainly.com/question/12625048
6 0
2 years ago
10: Convert 77.0 L at 18.0 mmHg to its new volume at standard pressure.
olchik [2.2K]

Answer:

The answer to your question is   V2 = 1.82 l

Explanation:

Data

Volume 1 = 77 l

Pressure 1 = 18 mmHg

Volume 2 = ?

Pressure 2 = 760 mmHg

Process

Use Boyle's law to solve this problem

                P1V1 = P2V2

-Solve for V2

                 V2 = P1V1/P2

-Substitution

                 V2 = (18 x 77) / 760

-Simplification

                 V2 = 1386 / 760

-Result

                 V2 = 1.82 l

5 0
3 years ago
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