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Alenkinab [10]
4 years ago
7

This reaction describes cellular respiration. C6H12O6 + 6O2 → 6CO2 + 6H2O Which compounds are the reactants and which are the pr

oducts? A. reactants: C6H12O6 + 6O2 products: 6CO2 + 6H2O B. reactants: 6CO2 + 6H2O products: C6H12O6 + 6O2 C. reactants: 6CO2 + C6H12O6 products: 6H2O + 6O2 D. reactants: 6H2O + 6O26CO2 + C6H12O6 products: 6CO2 + C6H12O6
Chemistry
2 answers:
mafiozo [28]4 years ago
6 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

In a chemical equation, the chemical species are termed as reactants or products.

Reactants are defined as the species which react in the reaction and are written on the left side of the reaction arrow.

Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.

For the given chemical equation:

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O

The chemical species written on the left side of the arrow are C_6H_{12}O_6\text{ and }6O_2. They are considered as reactants.

The chemical species written on the right side of the arrow are 6CO_2\text{ and }6H_2O. They are considered as products

Hence, the correct answer is Option A.

kherson [118]4 years ago
4 0
The reactants are C6H12O6 (Glucose) and 6O2 (Oxygen) and the products are 6CO2 (Carbon Dioxide) and 6H20 (Water)
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Does anyone know what Hydrogen's oxidation state would be if it was acting as an anion non-metal?
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05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
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Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

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Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

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Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

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