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3 years ago

Which process is responsible for the greatest loss of energy from Earth’s surface into space on a clear night?

1 answer:

6 0

The process that is responsible for the greatest loss of energy from the Earth's surface into space on a clear night is called radiation.

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The vapor pressure of water and the partial pressure of hydrogen contribute to the total pressure of 715 torr. What is the parti

Lostsunrise [7]

Answer:

0.91 atm is the partial pressure of just hydrogen gas.

Explanation:

Vapor pressure of water , p= 0.0313 atm

Partial pressure of hydrogen gas = $p_{H_2}$

Total pressure of the water vapors and hydrogen gas = P = 715 Torr

1 atm = 715 Torr

$715 Torr=\frac{715}{760} atm=0.94 atm$

According Dalton's law of partial pressure:

$P=p+p_{H_2}$

$0.94 atm=0.0313 atm+p_{H_2}$

$p_{H_2}=0.94 atm - 0.0313 atm =0.9087 atm \approx 0.91 atm$

0.91 atm is the partial pressure of just hydrogen gas.

8 0

3 years ago

A typical refrigerator is kept at 4˚C, and a soda can has a pressure of

ss7ja [257]

Answer: The new pressure will be 1.42 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=1.18atm\\T_1=4^0C=(4+273)K=277K\\P_2=?\\T_2=60^0C=(60+273)K=333K$

Putting values in above equation, we get:

$\frac{1.18}{277}=\frac{P_2}{333}\\\\P_2=1.42$

Hence, the new pressure will be 1.42 atm

7 0

3 years ago

HURRY !!!!!! How did kelper describe the planets Orbits ?

Andrei [34K]

Kepler's Laws of Planetary Motion. While Copernicus rightly observed that the planets revolve around the Sun, it was Kepler who correctly defined their orbits.

Sorry about the holds, copied it from google...

8 0

3 years ago

Question 11 (1 point)

erastova [34]

Answer:

remove product

Explanation:

Removing the product will always shift the equilibrium to the right. This is based on the Le Chatelier's principle which states that "if any of the conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".

If a system at equilibrium is disturbed, by changing the concentration of one of the substances all the concentrations will change until a new equilibrium point is reached.
Removing the product will increase the concentration of the species on the left hand side, the equilibrium will shift to the right.

5 0

3 years ago

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$