A person standing on the edge of a high cliff throws a rock straight up with an initial velocity, v0v0, of 13.0m/s13.0m/s. on th
e way back down the rock misses the edge of the cliff and continues to fall. ignoring the effects of air resistance, calculate the position and velocity of the rock a
For the position, we can use the equation below for our calculations: H = h + v₀²/2g where H is the total height from the base of the cliff to the highest point of the rock on air h is the height of the cliff v₀ is the initial height g is equal to 9.81 m/s²
H = h + 13²/2(9.81) H = h + 8.61 m
Because the height of the cliff is not known, the answer would just be h +8.61 m.
For the velocity, we use the equation: v = √2gH. Substituting the answer for H, the velocity is
Speed is the time rate of an object moving from one place to another, while velocity is the rate and direction of the object's movement. They are very similar but they don't mean the same thing.
