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Natasha2012 [34]
3 years ago
11

A person standing on the edge of a high cliff throws a rock straight up with an initial velocity, v0v0, of 13.0m/s13.0m/s. on th

e way back down the rock misses the edge of the cliff and continues to fall. ignoring the effects of air resistance, calculate the position and velocity of the rock a
Physics
1 answer:
Firdavs [7]3 years ago
8 0
For the position, we can use the equation below for our calculations:
H = h + v₀²/2g
where 
H is the total height from the base of the cliff to the highest point of the rock on air
h is the height of the cliff
v₀ is the initial height
g is equal to 9.81 m/s²

H = h + 13²/2(9.81)
H = h + 8.61 m

Because the height of the cliff is not known, the answer would just be h +8.61 m.

For the velocity, we use the equation: v = √2gH. Substituting the answer for H, the velocity is

v = √2(9.81)(h+8.61)
v = 4.43√(h+8.61)
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Re=160ohm

Explanation:

Step#1

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Say you want to make a sling by swinging a mass M of 2.3 kg in a horizontal circle of radius 0.034 m, using a string of length 0
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Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

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However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

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you replace this value of v in the equation (1). Also, you replace the values of r and m:

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