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seropon [69]
3 years ago
15

A car of mass 487 kg travels around a flat, circular race track of radius 53.3 m. The coefficient of static friction between the

wheels and the track is 0.19. The acceleration of gravity is 9.8 m/s 2 . What is the maximum speed v that the car can go without flying off the track? Answer in units of m/s.
Physics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

9.96 m/s

Explanation:

mass of car, m = 487 kg

radius of track, R = 53.3 m

coefficient of static friction, μ = 0.19

acceleration due to gravity, g = 9.8 m/s^2

let v be the maximum speed so that the car can go without flying off the track.

The formula for the maximum speed is given by

v_{max}=\sqrt{\mu Rg}

v_{max}=\sqrt{0.19\times53.3\times9.8

vmax = 9.96 m/s

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6 0
3 years ago
A bus starts from rest.if the acceleration is 2m/s square, find
MrMuchimi

Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

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s= 4 meters

Explanation:

3 0
1 year ago
A bat can detect small objects such as an insect whose size is approximately equal to the wavelength of the sound the bat makes.
slamgirl [31]

Answer:

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Explanation:

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So here we can say that the wavelength of sound is the ratio of speed of sound and its frequency

here we know that

speed of sound in air is 536 m/s

frequency of sound is 33.3 kHz

so here we can say

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7 0
3 years ago
A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d
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Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

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d  = 35 cm = 0.35 m

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F = m g

\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg

Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}

(b) By substituting the values

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Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

4 0
3 years ago
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