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mr_godi [17]
3 years ago
14

Solve the system of equations: -5x+y-4z=60 2x+4y+3z=-12 6x-3y-2x=-52

Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

The answer to your question is:

x = -8; y = 1 ; z = -4

Step-by-step explanation:

Δ = \left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right]

  = 40 + 24 + 18 - (-4 + 45 - 96)

 = 82  + 55

 = 137

Δx = \left[\begin{array}{ccc}60&1&-4\\-12&4&3\\-52&-3&-2\end{array}\right]

= - 480 - 144 - 156 - ( 24 - 540 + 832)

= -780 -316

= - 1096

Δy = \left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right]

= 40 + 24 + 18 - ( - 4 + 45 - 96)

= 82 + 55

= 137

Δz = \left[\begin{array}{ccc}-5&1&60\\2&4&-12\\6&-3&-52\end{array}\right]

= 1040 - 360 - 72 - ( - 104 - 180 + 1440)

= 608 - 1156

= -548

x = -1096/ 137 = -8

y = 137 / 137 = 1

z = -548 / 137 = -4

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