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posledela
3 years ago
14

What general rule can be followed when choosing a type of solvent to dissolve a particular solid?

Chemistry
1 answer:
Fittoniya [83]3 years ago
4 0
 <span>the polarity of the solute or the solvent. 

for example: 
oil will not mix with water because oil molecules are nonpolar however water moleculses are polar. so, they will not mix with each other. 

when we put sodium chloride in water, sodium chloride will be easily dissoved. because both sodium chloride and water are polar. 

in other case, if we put sodium chloride and hexane together. sodium chloride will not dissove in hexane, because hexane is a nonpolar solvent. 

finally, if we try to mix hexane and bromine together, they will mix uniformly. because both hexane and bromine are nonpolar. (note: most diatomic molecules are nonpolar, such as hydrogen gas, oxygen gas, chlorine gas, etc. ) 

so just remember, nonpolar and nonpolar will dissovle each other. and polar and polar will dissolve each other.</span>
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How many moles are in 1.2x10^3 grams of ammonia(NH3) ?
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Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = 1.2\times 10^3g

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Formula used :

\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}

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Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
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Answer:

108.43 grams KNO₃

Explanation:

To solve this problem we use the formula:

  • ΔT = Kf * b * i

Where

  • ΔT is the temperature difference (14.5 K)
  • Kf is the cryoscopic constant (1.86 K·m⁻¹)
  • b is the molality of the solution (moles KNO₃ per kg of water)
  • and<em> i</em> is the van't Hoff factor (2 for KNO₃)

We <u>solve for b</u>:

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Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:

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Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:

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