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3 years ago

What general rule can be followed when choosing a type of solvent to dissolve a particular solid?

1 answer:

4 0

the polarity of the solute or the solvent.

for example:
oil will not mix with water because oil molecules are nonpolar however water moleculses are polar. so, they will not mix with each other.

when we put sodium chloride in water, sodium chloride will be easily dissoved. because both sodium chloride and water are polar.

in other case, if we put sodium chloride and hexane together. sodium chloride will not dissove in hexane, because hexane is a nonpolar solvent.

finally, if we try to mix hexane and bromine together, they will mix uniformly. because both hexane and bromine are nonpolar. (note: most diatomic molecules are nonpolar, such as hydrogen gas, oxygen gas, chlorine gas, etc. )

so just remember, nonpolar and nonpolar will dissovle each other. and polar and polar will dissolve each other.

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What is most likely the ph of a solution containing many hydroxide ions (oh-) and few hydrogen ions (h )?

SIZIF [17.4K]

PH of solution will be greater than seven (pH>7), that means that solution is basic (pH above 7 is a base, the higher the number, the stronger is the base).
pH (potential of hydrogenis) is a measure of the hydrogen ion (H⁺) concentration of a solution. Solutions with a pH less than 7 are acidic.

5 0

3 years ago

A 475 cm3 sample of gas at standard temperature and pressure is allowed to expand until it occupies a

Andrej [43]

The final temperature : 345 K

<h3> Further explanation </h3>

Given

475 cm³ initial volume

600 cm³ final volume

Required

The final temperature

Solution

At standard temperature and pressure , T = 273 K and 1 atm

Charles's Law :

When the gas pressure is kept constant, the gas volume is proportional to the temperature

V₁/T₁=V₂/T₂

Input the value :

T₂=(V₂T₁)/V₁

T₂=(600 x 273)/475

T₂=345 K

4 0

3 years ago

What is the result of crystals boiling the impure product with too much solvent and then cooling on ice?

VMariaS [17]

Answer: Option (c) is the correct answer.

Explanation:

It is known that when we tend to dilute an impure product with too much of solvent then it will lead to dissolution of the solute. As a result, the chances of formation of crystal reduces.

And, when we increase the temperature then there will occur increase in the number of collisions between the solute and solvent molecules.

Hence, solubility of the solute also increases with increase in temperature, placing it on ice bath will further reduce the crystal formation, hence no crystal should be formed in the reaction.

Thus, we can conclude that the result of crystals boiling the impure product with too much solvent and then cooling on ice is that no crystals are produced.

8 0

3 years ago

Vishwanath had some money. he spent 3 upon 4 part of money to buy goods for his birthday,1 upon 5 part of money give to his sist

lord [1]

Answer:

The correct answer is - 800.

Explanation:

Given:

Total amount = ? or assume x

spend in buying birthday item = 3/4 of x

given to sister = 1/5 of x

remaining to mother = 40

solution:

the remaning amount = x- (3x/4+x/5) = 4=

=> x- 19x/20 = 40

=> x = 20*40

=> x = 800

thus, the correct answer is = 800

8 0

2 years ago

A gaseous mixture composed of 20% CH4, 30% C2H4, 35% C2H2, and 15% C2H20. What is the average molecular weight of the mixture? a

Semenov [28]

Answer: The correct answer is Option d.

Explanation:

We are given:

Mass percentage of $CH_4$ = 20 %

So, mole fraction of $CH_4$ = 0.2

Mass percentage of $C_2H_4$ = 30 %

So, mole fraction of $C_2H_4$ = 0.3

Mass percentage of $C_2H_2$ = 35 %

So, mole fraction of $C_2H_2$ = 0.35

Mass percentage of $C_2H_2O$ = 15 %

So, mole fraction of $C_2H_2O$ = 0.15

We know that:

Molar mass of $CH_4$ = 16 g/mol

Molar mass of $C_2H_4$ = 28 g/mol

Molar mass of $C_2H_2$ = 26 g/mol

Molar mass of $C_2H_2O$ = 48 g/mol

To calculate the average molecular mass of the mixture, we use the equation:

$\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}$

where,

$\chi_i$ = mole fractions of i-th species

$m_i$ = molar masses of i-th species

$n_i$ = number of observations

Putting values in above equation:

$\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}$

$\text{Average molecular weight of mixture}=\frac{(0.20\times 16)+(0.30\times 28)+(0.35\times 26)+(0.15\times 42)}{4}\\\\\text{Average molecular weight of mixture}=6.75$

Hence, the correct answer is Option d.

3 0

3 years ago