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Pachacha [2.7K]

3 years ago

6

A student solving a physics problem for the range of a projectile has obtained the expression r= v20sin(2θ)g where v0=37.2meter/

second, θ=14.1∘, and g=9.80meter/second2. use your calculator to evaluate r.

2 answers:

Alika [10]3 years ago

6 0

The range of a projectile is about 66.7 m

$\texttt{ }$

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\boxed {a = \frac{v - u}{t} }$

$\boxed {d = \frac{v + u}{2}~t }$

<em>where:</em>

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

$\texttt{ }$

Let's recall Range of Projectile formula as follows:

$\boxed{ R = \frac{ v_o^2 \sin 2\theta}{g} }$

<em>where:</em>

<em>R = range of projectile ( m )</em>

<em>v₀ = initial speed of projectile ( m/s )</em>

<em>θ = angle of projection</em>

<em>g = gravitational acceleration ( m/s² )</em>

Let us now tackle the problem!

$\texttt{ }$

<u>Given:</u>

initial speed of projectile = v₀ = 37.2 m/s

angle of projection = θ = 14.1°

gravitational acceleration = g = 9.80 m/s²

<u>Asked:</u>

the range of a projectile = R = ?

<u>Solution:</u>

$R = \frac{ v_o^2 \sin 2\theta}{g}$

$R = \frac{ 37.2^2 \sin 2 (14.1^o)}{9.80}$

$\boxed {R = 66.7 \texttt{ m}}$

$\texttt{ }$

The range of a projectile is about 66.7 m

$\texttt{ }$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

$\texttt{ }$

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

DedPeter [7]3 years ago

5 0

Formula of range is given by

$R = \frac{v_o^2 sin2\theta}{g}$

here given that

$v_0=37.2m/s$

θ=14.1∘

$g=9.80m/s^2$

now by above equation

$R = \frac{37.2^2 sin2*14.1}{9.80}$

R = 66.7 m

so range will be 66.1 m

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