1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mariana [72]
2 years ago
12

A sled is pulled with a horizontal force of 18 n along a level trail, and the acceleration is found to be 0.39 m/s2. an extra ma

ss m = 4.5 kg is placed on the sled. if the same force is just barely able to keep the sled moving, what is the coefficient of kinetic friction between the sled and the trail?
Physics
1 answer:
Natali5045456 [20]2 years ago
5 0
From Newton's second law of motion, it is identified that the net force applied to the object with mass m, will make it move with an acceleration of a. This can be mathematically translated as,
                        F = m x a
To solve for the mass of the sled, we derive the equation above such that,
                        m = F / a
Substituting,
                       m = (18 N) / (0.39 m/s²)
                          m = 46.15 kg

Then, we add to the calculated mass the mass of the extra material.
                      total mass = 46.15kg + 4.5 kg
                       total mass = 50.65 kg
We solve for the normal force of the surface to the object by calculating its weight.
                     F₂ = (50.65 kg)(9.8 m/s²)
                     F₂ = 496.41 N

The force that would allow barely a movement for the object is equal to the product of the normal force and the coefficient of kinetic friction.
                     F = (F₂)(c)
                      c = F/F₂

Substituting,
                      c = 18 N/496.41 N
                       c = 0.0362

<em>ANSWER: c = 0.0362</em>

You might be interested in
PLEASE HELP!!!! Thank you!
V125BC [204]

it would be a chain reaction and a wave

6 0
3 years ago
I just need help with these seven!
Anna [14]
21. light changes its direction when travelling through a new medium because denser mediums have a higher angle of refraction.
5 0
3 years ago
an ice skater applies a horizontal force to a 20.-kilogram block on frictionless, level ice, causing the block to accelerate uni
stiv31 [10]
The only vertical forces are weight and normal force, and they balance since the surface is horizontal. The horizontal forces are the applied force (uppercase F) in the direction the block slides and the frictional force (lowercase f) in the opposite direction.

Apply Newton's 2nd Law in the horizontal direction:
ΣF = ma
F - f = ma
where f = µmg

F - µmg = ma
F = m(a +µg)
F = (20 kg)(1.4 m/s² + 0.28(9.8 m/s²)

F = 83 N
3 0
3 years ago
Magnetic fields exist
Effectus [21]

Answer:

Magnetic fields exist near a magnet, farther away from a magnet, and within a magnet.

So, the answer is D. All of the above.

Let me know if this helps!

6 0
3 years ago
A machine can never be 100% efficient because some work is always lost due to .
klasskru [66]
Friction
Hope it helped
5 0
3 years ago
Read 2 more answers
Other questions:
  • In a physics lab, light with a wavelength of 490 nm travels in air from a laser to a photocell in a time of 17.5 ns . When a sla
    11·1 answer
  • Will give brainliest!
    8·1 answer
  • What will happen to plant height if the amount of available light is reduced due to global dimming?
    8·1 answer
  • What is the density of alcohol?​
    14·1 answer
  • What kind of electric cell is considered to be rechargeable?
    7·2 answers
  • I WILL MARK BRAINLIEST
    5·2 answers
  • 2. What is the reason for spherometer stands on three legs?​
    15·2 answers
  • Use the scenario below for questions 4-7.
    11·1 answer
  • A Gaussian surface in the form of a hemisphere of radius R = 3.04 cm lies in a uniform electric field of magnitude E = 1.64 N/C.
    12·1 answer
  • Non-polarized capacitors are also referred to as __________ or ac capacitors can be used on both ac and dc circuits.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!