Answer:
.122 mols of KCl
Explanation:
<u>Read the explanation </u><u><em>while</em></u><u> looking at the picture.</u>
We star with 15g because it's wat they give us:
<u>15g of KCIO3 will cancel out with 123g of KCIO3</u> (molar mass)
~Grams of KCIO3 are canceled out.~
<u>That 123g of KCIO3 is the same as 1 mol of KCIO3</u>
Then we use mole to mole ratio:
<u>1 mol of KCIO3 equals 2 mols of KCIO3</u> -- 2 moles from the equation
The <u>2 mols of KCIO3 is equal to 2 mols of KCl</u> (from equation)
Multiply the numbers on top. Multiply the numbers on the bottom. Then divide. You get:
This sounds confusing. But the picture below is the format.
The SAME COLOR are the ones that cancel out.
1.1943571. The molar mass of K3PO4 is 212.27. After using stochieometry, you get your answer.
For a hydrogen atom, composed of an orbiting electron bound to a nucleus of one proton, an ionization energy of 2.18 × 10−18 joule (13.6 electron volts) is required to force the electron from its lowest energy level entirely out of the atom.