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3 years ago

Write the formula for the polyatomic ion of ba3(po4)2: express your answer as an ion. express single charges as [+], not [1+]

1 answer:

8 0

Ba₃(PO₄)₂ is a compound made of a metal cation and polyatomic ion.
polyatomic ion is when 2 or more atoms are covalently bonded together and together have a charge and can act as one compound that can bond with another atom.
In this case Ba²⁺ is the metal cation and PO₄³⁻ is the polyatomic ion. this is called the phosphate ion. one phosphate atom is bonded to 4 O atoms with an net charge of -3 and acts as a single unit.

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Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other equations, and balance them. Check your answer

suter [353]

Answer: See below

Explanation:

To balance equations, you want to have the same amount of elements on the product and reactants side.

__Al+ __HCl→__AlCl₃+ __H₂

We see that there are 3 Cl on the products side and 1 on the reactants side, but there are 2 H on the product and 1 on reactant. To fulfill them both, let's put a 6 at HCl.

__Al+ 6HCl→__AlCl₃+ __H₂

Now that we have a 6 at HCl, we can fill in AlCl₃ and H₂.

__Al+ 6HCl→ 2AlCl₃+ 3H₂

All we have left is to fill in Al.

2Al+ 6HCl→ 2AlCl₃+ 3H₂

-----------------------------------------------------------------------------------------------------------------

__NaCl→ __Na+ __Cl₂

Since we have 2 Cl on the products, we must put 2 on the reactants.

2NaCl→ __Na+ 1Cl₂

With 2 NaCl, we can fill in Na.

2NaCl→ 2Na+ 1Cl₂

-----------------------------------------------------------------------------------------------------------------

__Na₂S+ __HCl→ __NaCl+ __H₂S

We see 2 Na on reactants, so we can put 2 on the products.

__Na₂S+ __HCl→ 2NaCl+ __H₂S

With 2 H and 2 Cl on the products, we can put a 2 at HCl.

1Na₂S+ 2HCl→ 2NaCl+ 1H₂S

7 0

3 years ago

In one compound of nitrogen and oxygen, 0.615 grams of nitrogen combines with 0.703 grams of oxygen. In another 1.27 grams of ni

Orlov [11]

Answer:

Answer in explanation

Explanation:

In the first case, we divide each of the masses by the respective atomic masses:

N =0.615/14 = 0.043928571428571

O = 0.703/16 = 0.0439375

It can be seen here that the values are similar, hence the formula is NO

now let us look at the second data set:

N = 1.27/14 = 0.090714285714286

O = 2.9/16 = 0.18125

We now divide by the smallest

N = 090714285714286/090714285714286 = 1

O = 0.18125/090714285714286 = 2

The formula here is thus NO2.

It can be seen that there are different oxides of nitrogen here which clearly indicates the law of multiple proportion.

4 0

3 years ago

The cubic centimeter (cm' or cc) has the same volume as a

snow_lady [41]

The answer is B milliliter

3 0

3 years ago

How many moles of HNO3 are present if 4.90×10−2 mol of Ba(OH)2 was needed to neutralize the acid solution?

Amiraneli [1.4K]

Answer:

0.098 moles

Explanation:

Let y represent the number of moles present

1 mole of Ba(OH)₂ contains 2 moles of OH- ions.

Hence, 0.049 moles of Ba(OH)2 contains y moles of OH- ions.

To get the y moles, we then do cross multiplication

1 mole * y mole = 2 moles * 0.049 mole

y mole = 2 * 0.049 / 1

y mole = 0.098 moles of OH- ions.

1 mole of OH- can neutralize 1 mole of H+

Therefore, 0.098 moles of HNO₃ are present.

3 0

3 years ago

A chemist dissolves 581.1mg of pure perchloric acid in enough water to make up 150 ml of solution. Calculate the pH of the solut

algol [13]

<u>Answer:</u> The pH of the solution is 1.41

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of perchloric acid = 581.1 mg = 0.5811 g (Conversion factor: 1 g = 1000 mg)

Molar mass of perchloric acid = 100.5 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

$\text{Molarity of perchloric acid}=\frac{0.5811\times 1000}{100.5\times 150}\\\\\text{Molarity of perchloric acid}=0.0385M$

1 mole of perchloric acid produces 1 mole of $H^+$ ions and 1 mole of $ClO_4^-$ ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.0385M$

Putting values in above equation, we get:

$pH=-\log (0.0385)=1.41$

Hence, the pH of the solution is 1.41

6 0

3 years ago