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Fudgin [204]
3 years ago
12

What is the net force in the x-direction? 30 N 34 N 55 N 65 N

Physics
2 answers:
Soloha48 [4]3 years ago
5 0

Answer:

The answer is 34 N

Explanation:

Hope this helped!!!

Zigmanuir [339]3 years ago
4 0

<u>Answer </u>


34 N


<u>Explanation.</u>

I think the question is not complete.. It should be "<em>A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"</em>


We should find the horizontal component of the force 65 N.

Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.


cosФ = adjacent/hypotenuse


let x be the net required (the component of 65N)

cos 58 = x/65

x = 65 × cos 58

= 34.44 N

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