Question

What is the initial drag force for a golf ball with the following conditions? Frontal area: 14 cm2 (remember to convert to m2), air density: 1.204 kg/m3, initial velocity: 50 m/s, coefficient of drag: 0.3

Answer 1

Answer:

F= 0.6321 N

Explanation:

Given

Area ,A= 14 cm²

Density ,ρ = 1.204 kg/m³

Velocity ,v= 50 m/s

Drag coefficient ,C=0.3

The drag force on the golf given as

$F=\dfrac{1}{2}\rho CAv^2$

Now by putting the values

$F=\dfrac{1}{2}\rho CAv^2$

$F=\dfrac{1}{2}\times 0.3\times 1.204 \times (14\times 10^{-4})\times 50^2\ N$

F= 0.6321 N

Therefore force due to drag on the golf is 0.6321 N