What can a base substance do to a hydroxide ion A.DONATE B.ACCEPT OR C.BOND WITH

A child of mass M is swinging on a swing set. The ropes attaching the swing to the top bar have length L. Find the gravitational

myrzilka [38]

Answer:

(a) 0

(b) 10ML

(c) $10ML(1 - cos(\theta))$

(d) $10ML(1 + sin(\phi))$

Explanation:

(a) When hanging straight down. The child is at the lowest position. His potential energy with respect to this point would also be 0.

(b) Since the rope has length L m. When the rope is horizontal, he is at L (m) high with respect to the lowest swinging position. His potential energy with respect to this point should be

$E_h = mgh = 10ML$

where g = 10m/s2 is the gravitational acceleration.

(c) At angle $\theta$ from the vertical. Vertically speaking, the child should be at a distance of $Lcos(\theta)$ to the swinging point, and a vertical distance of $L - Lcos(\theta)$ to the lowest position. His potential energy to this point would be:

$E_{\theta} = mgh = 10M(L - Lcos(\theta)) = 10ML(1 - cos(\theta))$

(d) at angle $\phi$ from the horizontal. Suppose he is higher than the horizontal line. This would mean he's at a vertical distance of $Lsin(\phi)$ from the swinging point and higher than it. Therefore his vertical distance to the lowest point is $L + Lsin(\phi) = L(1 + sin(\phi))$

His potential energy to his point would be:

$E_{\phi} = mgh = 10ML(1 + sin(\phi))$

5 0

4 years ago

An object’s speed is the distance it travels _____ the amount of time it takes.

steposvetlana [31]

An objects speed is the distance it travles DIVIDED by the amount of time it takes

6 0

4 years ago

Read 2 more answers

Bryan Allen pedaled a human-powered aircraft across the English Channel from the cliffs of Dover to Cap Gris-Nez on June 12, 197

Leno4ka [110]

(a) 3.58 km 45° south of east

The total displacement is given by:

$d=vt$

where

v is the average velocity

t is the time

The average velocity is:

v = 3.53 m/s

While we need to convert the time from minutes to seconds:

$t=169 min \cdot 60 s/min = 10140 s$

Therefore, the magnitude of the displacement is

$d=(3.53)(10140)=35794 m = 3.58 km$

And the direction is the same as the velocity, therefore 45° south of east.

(b) 5.53 m/s 90° south of east

The velocity of the air relative to the ground is

$v_a = 2.00 m/s$

and the direction is exactly opposite to that of Allen, so it is 45° north of west. Allen's velocity relative to the ground is

v = 3.53 m/s

So this must be the resultant of Allen's velocity relative to the air (v') and the air's speed ( $v_a$ ). Since these two vectors are in opposite direction, we have

$v= v'-v_a$

Therefore we find v', Allen's velocity relative to the air:

$v'=v+v_a = 3.53 + 2.00 = 5.53 m/s$

The direction must be measured relative to the air's reference frame. In this reference frame, Allen is moving exactly backward, so his direction will be 90° south of east.

(c) 56.1 km at 90° south of east.

Since Allen's velocity relative to the air is

v' = 5.53 m/s

Then the displacement of Allen relative to the air will be given by

$d'=v't$

and substituting,

$d'=(5.53)(10140)=56074 m = 56.1 km$

And the direction is the same as that of the velocity, therefore will be 90° south of east.

3 0

4 years ago

For the following, determine the final volume in ml (V2) of a gas when it is heated to 373K (T2) when it's starting temperature

Ksju [112]

Answer:

136.63 ml

Explanation:

3 0

2 years ago

What type of wave has rarefactions?

mamaluj [8]

Sound waves is a type of with rarefraction.

3 0

4 years ago