A 20.0-kg package is dropped from a high tower in still air and is "tracked" by a radar system. When the package is 25 m above t
1 answer:
Answer:
56 N
Explanation:
There are only two forces acting on the package:
- The force of gravity, directed downward, equal to
where m is the mass of the package and g is the acceleration due to gravity
- The air resistance, acting upward, let's label it with
According to Newton's second law, the resultant of the two forces must be equal to the product between the mass, m, and the acceleration, a:
where we have:
m = 20.0 kg
g = 9.8 m/s^2
a = 7.0 m/s^2 is the acceleration when the package is at 25 m above the ground.
Substituting into the equation, we can find the magnitude of the air resistance at that altitude:
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So, in order for the additional electron to cross this point, it is required an infinite amount of work, which is impossible.
In fact, assuming the additional electron is coming from the positive direction, as it approaches x=+1.00 m it will become closer and closer to the electron located at x=+1.00 m. However, the electrostatic force between the two electrons (which is repulsive) will become infinite when the second electron reaches x=+1.00 m, because the distance d between the two electrons is zero:
So, in order for the additional electron to cross this point, it is required an infinite amount of work, which is impossible.