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Neko [114]
3 years ago
13

A certain quantity of matter is called WHAT?

Chemistry
2 answers:
Lerok [7]3 years ago
6 0
A certain quantity of matter is called mass.
Ierofanga [76]3 years ago
5 0
A certain qaunity of matter could be Mass
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6 1 point If John kicks a soccer ball with 12 N of force and the ball accelerates at 25 m/s2. what is the mass of the ball? 13 k
grin007 [14]

Answer:

<h3>m=0.48k.g</h3>

Explanation:

<h3>f=m×a......m=f/a</h3><h3>m=12n/25m/s^2</h3><h3>m=0.48k.g</h3>
7 0
3 years ago
What is the limiting reactant if 10 moles of NH 3 react with 30.0 moles of NO ?
Elis [28]

Answer:

NO is the limiting reactant.

Explanation:

4NH3 + 6NO --> 5N2 + 6H2O

Molar ration NH3 : NO = 10: 30 = 1: 3

Stoichiometric molar ration NH3:NO = 4:6 = 2:3

NO is the limiting reactant.

5 0
3 years ago
If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically
Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = \frac{mass}{atomic mass of 1 mole}

putting the values in the equation

NaOH = \frac{842}{39.9}

           = 21.1 MOLES OF NaOH

Al = \frac{750}{26.9}

   = 27.8 moles

from the equation

 from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

\frac{1}{3} = \frac{x}{21.1}

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

          = 548.55 grams

theoretical  yield from the given data is 548.55 grams

3 0
3 years ago
Which one is the ionic compound?​
Margarita [4]

Answer:

NAF IS AN IONIC COMPOUND

Explanation:

3 0
3 years ago
Read 2 more answers
A 645 g piece of iron is plunged into 375 g of water. The temperature of the water increases from 26 C to 87 C. If the heat capa
jeka94

Answer:

417 °C

Explanation:

From the question given above, the following data were obtained:

Mass of iron (Mᵢ) = 645 g

Specific heat capacity of iron (Cᵢ) = 0.449 J/gºC

Mass of water (Mᵥᵥ) = 375 g

Initial temperature of water (Tᵥᵥ) = 26 °C

Equilibrium temperature (Tₑ) = 87 °C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Initial temperature of iron (Tᵢ) =?

The initial temperature of iron can be obtained as follow:

Heat lost by iron = heat gain by water

MᵢCᵢ(Tᵢ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

645 × 0.449(Tᵢ – 87) = 375 × 4.184 (87 –26)

289.605(Tᵢ – 87) = 1569 × 61

289.605Tᵢ – 25195.635 = 95709

Collect like terms

289.605Tᵢ = 95709 + 25195.635

289.605Tᵢ = 120904.635

Divide both side by 289.605

Tᵢ = 120904.635 / 289.605

Tᵢ ≈ 417 °C

Thus, the original temperature of the iron is 417 °C

7 0
3 years ago
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